A 5.00-g bullet leaves the muzzle of a rifle with a speed of 320 m/s. the expanding gases behind it exert what force on the bull
et while it is traveling down the barrel of the rifle, 0.820 m long? assume constant acceleration and negligible friction.
1 answer:
Answer;
= 312 Newtons
Explanation;
The bullet has a mass of 0.005 kg, and a velocity of 320 m/s, so we need to find it's final kinetic energy.
KE = 1/2*m*v^2
= 1/2*0.005*320^2
= 256 Joules.
Divide this by the distance over which this energy was received and you have the force that provided that energy.
= 256/0.820 = 312.195 Newtons
Rounded off, this is 312 N
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C I completed the same quiz
Answer:
The position on the x axis is 0.32 m.
Explanation:
Given that,
Point charge = 27 nC
Charge = 6 nC
Distance = 1
We need to calculate the distance
Using formula of electric field
Put the value into the formula
Hence, The position on the x axis is 0.32 m.
I think the answer is b.boom
