1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MissTica
2 years ago
9

A backyard swimming pool with a circular base of diameter 6.00m is filled to depth 1.50m. (b) Two persons with combined mass 150

kg enter the pool and float quietly there. No water overflows. Find the pressure increase at the bottom of the pool after they enter the pool and float.
Physics
1 answer:
Mashutka [201]2 years ago
4 0

The pressure increase at the bottom of the pool after they enter the pool and float is 106.103 Pa.

<h3>What is absolute pressure?</h3>

Absolute pressure is the force that exists in a space when there is no matter present, or when there is a perfect vacuum. This absolute zero serves as the baseline for measurements in absolute pressure. The measurement of barometric pressure is the greatest illustration of an absolute referenced pressure. In order to determine absolute pressure, a complete vacuum is used. In contrast, gauge pressure is the amount of pressure that is measured in relation to atmospheric pressure, also referred to as barometric pressure.

given,

diameter = 6 m

depth = h = 1.5 m

Atmospheric pressure = P₀ = 10⁵ Pa

a) absolute pressure

P = P₀ + ρ g h

P = 10⁵ + 1000 x 10 x 1.5

P = 1.15 x 10⁵ Pa

b) When two person enters into the pool,

mass of the two person = 150 Kg

weight of water level displaced exists equal to the weight of person.

\rho \mathrm{Vg}=2 \mathrm{mg} \\

V=\frac{2 m}{\rho} \\

V=\frac{2 \times 150}{1000} \\

\mathrm{~V}=0.3 \mathrm{~m}^3

Area of pool $=\frac{\pi}{4} d^2$

&=\frac{\pi}{4} \times 6^2 \\

&=28.27 \mathrm{~m}^2

Height of the water rise

h &=\frac{V}{A} \\

h &=\frac{0.3}{28.27} \\

& \mathrm{~h}=0.0106 \mathrm{~m}

  • Pressure increased

P = ρ g h

P = 1000 x 10 x 0.0106

P = 106.103 Pa

To learn more about absolute pressure refer to:

brainly.com/question/17200230

#SPJ4

You might be interested in
Malika is writing an essay about the Sun. Below is the first paragraph in the essay. The Sun is an average-size star that is loc
djverab [1.8K]
The 109 Earth's the sun can hold over billion Earth's
8 0
3 years ago
Read 2 more answers
A playground carousel is free to rotate about its center on frictionless bearings, and air resistance is negligible. The carouse
Sidana [21]

Answer:

m = 35.98 Kg ≈ 36 Kg

Explanation:

I₀ = 125 kg·m²

R₁ = 1.50 m

ωi = 0.600 rad/s

R₂ = 0.905 m

ωf = 0.800 rad/s

m = ?

We can apply The law of conservation of angular momentum as follows:

Linitial = Lfinal

⇒    Ii*ωi = If*ωf   <em>(I)</em>

where    

Ii = I₀ + m*R₁² = 125 + m*(1.50)² = 125 + 2.25*m

If = I₀ + m*R₂² = 125 + m*(0.905)² = 125 + 0.819025*m

Now, we using the equation <em>(I) </em>we have

(125 + 2.25*m)*0.600 = (125 + 0.819025*m)*0.800

⇒  m = 35.98 Kg ≈ 36 Kg

5 0
3 years ago
The net electric charge of an amber rod which has been rubbed with fur is called negative Group of answer choices because amber
bonufazy [111]

Answer:

The right option is option E. None of the answer choices given are totally correct.

Explanation:

All insulators normally have an equal amount of positive and negative charges distributed on their surface.

The amber rod (an insulator) is called negative because after the coming together with fur (another insulator), the amber rod rubs off electrons from the fur onto itself and has an overall more negatively charged particles than positively charged particles on its surface.

The fur in turn becomes positive because it has more positive charges than negative on its surface.

So, the convention allows the now rubbed off amber rod to be called negative.

So, it is evident that none of the answer choices are totally correct, the right answer is more of a mix of some of the answer choices and more!

Hope this helps!!

3 0
3 years ago
If a car was cruising down the highway at 80 km/hr, how fast would the people inside the car be traveling?
wolverine [178]
Because the people in the car are attached to the vehicle, the people inside the vehicle are going the same speed as the vehicle.

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
Static electricity occurs when two objects have different electrical charges. When objects are rubbed together, the electrons fr
denis23 [38]

Answer:Alter your winter wardrobe. Wearing your favorite wool sweater or socks might seem perfect for keeping warm, but your chances of being shocked will rise while wearing wool and certain synthetic fabrics, including nylon and polyester. ...

Humidify your home. ...

Use dryer sheets. ...

Keep touching metal.

Explanation:hope that helps

5 0
3 years ago
Read 2 more answers
Other questions:
  • What is the distance between two spheres, each with a charge of 2.5 x 10-6 c, when the force between them is 0.50 n?
    14·1 answer
  • A small rubber ball is launched by a compressed-air cannon from ground level with an initial speed of 17.3 m/s directly upward.
    15·1 answer
  • Which of the following is an observation only? *
    9·1 answer
  • A hollow, transparent plastic tube is placed on a horizontal surface. A wire carrying a current is wound once around the tube to
    5·1 answer
  • A. Draw the wave that results when the two waves shown interact through destructive interference. (Image attached)
    9·2 answers
  • Which property of substances help to make a thermometer?<br> I NEED HELP.
    11·1 answer
  • At an amusement park there are 200-kg bumper cars A, B, and C that have riders with masses of 55 kg, 90 kg, and 42.5 kg respecti
    11·1 answer
  • A 2500-kg car is being pushed up a hill at an angle of 35 degrees. Determine the gravitational
    12·1 answer
  • What is the kinetic energy of a 36N toy car which is moving at 5 m/s?
    10·1 answer
  • What is the angular momentum at a radius of 2 m with an object of 5 kg at a<br> velocity of 20 m/s?
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!