Answer:
The body has negative acceleration PR a deceleration.
Explanation:
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The answer is λ₂ = 6.48 cm or 6.52 cm.
The out-of-tune guitar may have a wavelength between "6.48 cm" and "6.52 cm."
fb = |f2 − f1|
f₁ = 343/0.064
= 5276Hz
f₂ = 5276.9 Hz ± 17 Hz
f₂ = 5293.9 Hz or 5259.9 Hz
Now, calculating the possible wavelengths:
λ = 343/ 5259.9 or 343/ 5293.9
λ₂ = 6.48 cm or 6.52 cm
<h3>Why is beat frequency important?</h3>
When two waves with almost identical frequencies traveling in the same direction collide at a certain location, beats are produced. The opposing beneficial and harmful disruption causes the sound to alternatively be loud and weak whenever two sound waves with different frequencies reach your ear. This is referred to as beating.
The entire value of the frequency difference between the two waves is the beat frequency.
The following formula yields the beat frequency:
fb = |f2 − f1|
Learn more about beat frequency here:
brainly.com/question/14705053
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Answer:
time rising = 34 / 9.8 = 3.47 sec
total time in air = 2 * 3.47 sec = 6.94 sec
(time rising must equal time falling)
R = 17 m/s * 6.94 s = 118 m
Can also use range formula
R = v^2 sin (2 theta) / g
tan theta = 34 / 17 = 2
theta = 63.4 deg
2 theta = 126.9 deg
sin 126.9 = .8
v^2 = 17^2 + 34^2 = 1445 m^2/s^2
R = 1445 * .8 / 9.8 = 118 m agreeing with answer found above
Answer:
<h3>What is the angular speed of the earth around the sun? </h3>
It takes the Earth approximately 23 hours, 56 minutes and 4.09 seconds to make one complete revolution (360 degrees). This length of time is known as a sidereal day. The Earth rotates at a moderate angular velocity of

<h3>
What is the tangential speed of the earth? </h3>
The earth rotates once every 23 hours, 56 minutes and 4.09053 seconds, called the sidereal period, and its circumference is roughly 40,075 kilometers. Thus, the surface of the earth at the equator moves at a speed of 460 meters per second--or roughly 1,000 miles per hour.
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