Answer:
0.9177
Step-by-step explanation:
let us first represent the two failure modes with respect to time as follows
R₁(t) for external conditions
R₂(t) for wear out condition ( Wiebull )
Now,

where t = time in years = 1,
n = failure rate constant = 0.07
Also,

where t = time in years = 1
where Q = characteristic life in years = 10
and B = the shape parameter = 1.8
Substituting values into equation 1

Substituting values into equation 2

let the <em>system reliability </em>for a design life of one year be Rs(t)
hence,
Rs(t) = R1(t) * R2(t)
t = 1
![Rs(1) = [e^{-0.07} ] * [e^{-0.0158} ] = 0.917713](https://tex.z-dn.net/?f=Rs%281%29%20%3D%20%5Be%5E%7B-0.07%7D%20%5D%20%2A%20%5Be%5E%7B-0.0158%7D%20%5D%20%3D%200.917713)
Rs(1) = 0.9177 (approx to four decimal places)
This is a 30-60-90 triangle. The short leg is given to us as 5
The long leg is equal to sqrt(3) times the short leg
long leg = sqrt(3)*(short leg)
long leg = sqrt(3)*5
long leg = 5*sqrt(3)
The base is 5. The height is 5*sqrt(3)
b = 5
h = 5*sqrt(3)
Use this to find the area
A = b*h/2
A = 5*5*sqrt(3)/2
A = 25*sqrt(3)/2
which is the exact area in terms of a radical
You can write it out as
Answer: D
Step-by-step explanation: the answer is d because it can be simplified more
Answer:
1000
Step-by-step explanation:
see how to solve in pic
Answer:
5.8
Step-by-step explanation:
2.9*2=5.8 give brainliest pls