Answer:
Hey there!
The correct answer would be option A. If one body is positively charged and another body is negatively charged, free electrons tend to move from the negatively charged body to the positively charged body
Let me know if this helps :)
Answer:
Explanation:
a ) Applying law of conservation mechanical energy
1/2 mv² = mgh
v =√ 2gh
= √ 2 x 9.8 x 3
= 7.67 m /s
b ) Applying law of conservation of momentum
m x 7.67 = ( m + 2m ) v
= 3m v
v = 2.55 m /s
In perfectly inelastic collision , mechanical energy is not conserved.
Initial kinetic energy
= 1/ 2 x m x v²
= .5 x m x 58.8
= 29.4 m
Kinetic energy after collision
= .5 x 3m x (2.55) ²
= 9.75375 m
Loss of kinetic energy
= 19.646 m
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Answer:
A. T₁ = 7.204 N
B. T₂ = 19.07 N
C. I = 0.011979 kg * m²
Explanation:
Given
m₁ = 2.02 kg , d = 0.120 m, m₂ = 3.06 kg, s = 1.17 m, t = 0.810s
The tension can be find using the conserved energy in each axis so:
∑Fₓ = T₁ = m₁ * a₁
∑Fy = m₂ * g - T₂ = m₂ * a₁
Now to find the acceleration can use the equation of Newton motion
s = v₁* t + ¹/₂ * a₁ * t ²
Solve to a'
a₁ = 2* s / t ² = 2 * 1.17 m / (0.810 s)²
a₁ = 3.566 m/s²
A).
T₁ = m₁ * a₁ = T₁ = 2.02 kg * 3.566 m/s²
T₁ = 7.204 N
B).
T₂ = m₂ *(g - a₁) = 3.06 kg *(9.8 - 3.566) m/s²
T₂ = 19.07 N
C).
Finally to find the moment of inertia use the equation
∑ T = (T₂ - T₁) * r = I * α
α = a₁ / r
I = (T₂ - T₁ )* r²/ a₁
I = ( 19.07 - 7.204)* (0.06 m)² / 3.566 m/s²
I = 0.011979 kg * m²
Answer:
0.24 kg used up
Explanation:
He has a mass of 67 kg
The gravitational constant is 9.81 m/s^2
The distance upward is 3500 m
W = m*g*h
W = 67 * 9.81 * 3500
Work = 2,300,445 Joules
Work = 2300 kj
work = 2.30 * 10^6 joules in scientific notation.
Part B
He needs 4 times this amount to climb the mountain because the body is only 25% efficient in converting energy.
4*2.30 * 10^6 = 9.20 * 10^6 Joules of energy are therefore required.
The total amount in a kg of fat = 3.8 * 10^7 joules
x kg of fat is needed to provide 9.20.*10^6 joules
1 kg / (3.8 * 10^7 J ) = x kg / (9.20 * 10^6 J)
9.20 * 10 ^6 * 1 = 3.8 * 10^7 *x
9.20 * 10 ^6 / 3.8 * 10^7 = x
x = 0.24 kg of fat are needed