Question

A rocket is fired vertically upward. At the

Answer 1

Answer:

767.6 m/s

Explanation:

We consider momentum in both x and y components

Since momentum, p=mv where m denote mass while v is velocity then

In the y direction

3m*288=279m+my

y=585 m/s

In the x direction and taking right as positive then

3m*288=367m+mx

x=497 m/s

The resultant gives the velocity of the third fragment

$Third=\sqrt{585^{2}+497^{2}}=767.6157893\approx 767.6 m/s$