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adell [148]
3 years ago
10

Answer question 83 and 84

Physics
1 answer:
Ne4ueva [31]3 years ago
6 0
83. Gravity is activity as a force on the cart.

84. The box has gathered kinetic energy and momentum and will continue going forward.
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Help me with this plzzz
Marysya12 [62]

Answer:

yeah I'm Pretty sure it's b

4 0
3 years ago
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Constructive and destructive interference of vibrational waves on an aircraft can create a range of effects from a slight tail f
horrorfan [7]

Answer:

A. True

Explanation:

This is because these aircraft experiences different types of vibrations which include buffet vibrations and aerodynamic flutter. Buffet vibrations are vibrations caused by an interruption of airflow. Buffet vibrations are usually felt when the aerodynamic brakes are applied.

Aeroelastic flutter is the most dangerous type of vibration. This occurs when energy added to the wings due to airflow is greater than that lost due to damping. Aeroelastic flutter can cause aircraft to fail when the vibrations are large enough.

3 0
2 years ago
A 15.0 mW laser puts out a narrow beam 2.00 mm indiameter.
Murljashka [212]

Answer:

1341.03 V/m

Explanation:

The power output per unit area is the intensity and also the is the magnitude of the Poynting vector.

                                 S = \frac{P}{A} = cε₀E^{2} _{rms}

                             ⇒ \frac{P}{A} = cε₀E^{2}_{rms}

Where;

P is the power output

A is the area of the beam

c is speed of light

ε₀ is permittivity of free space 8.85 × 10⁻¹² F/m

E_{rms} is the average (rms) value of electric field

Making electricfield E_{rms} the subject of the equation

                                 E^{2}_{rms} = P / Acε₀

                                 E_{rms} = √(P / Acε₀)

But area A = πr²

                                 E_{rms} = √(P / πr²cε₀)                    

Given:

Output power, P = 15 mW = 0. 015 W

Diameter, d = 2 mm = 0.002 m

⇒ Radius, r = \frac{d}{2} = \frac{0.002}{2} = 0.001 m

Solving for average (rms) value of electric field;     

E_{rms} = \sqrt{\frac{0.015 W}{\pi * (0.001 m)^2 * (3 * 10^8 m/s) * (8.85 * 10^-12) C^2/Nm^2} }

                                E_{rms} = 1341.03 V/m

                             

                         

                                 

                                 

                                 

6 0
3 years ago
I need help with this answer I believe it's a democracy​
kipiarov [429]

Answer:

a. democracy

Explanation:

beacouse the government control of their members

8 0
2 years ago
In his novel From the Earth to the Moon (1866), Jules Verne describes a spaceship that is blasted out of 12,000 yards/s. the Col
saw5 [17]

Answer:

The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.

Explanation:

Let suppose that spaceship is accelerated uniformly. A yard equals 0.914 meters. A feet equals 0.304 meters. If air viscosity and friction can be neglected, then acceleration (a), measured in meters per square second, is estimated by this kinematic formula:

a = \frac{v^{2}-v_{o}^{2}}{2\cdot \Delta s } (1)

Where:

\Delta s - Travelled distance, measured in meters.

v_{o}, v - Initial and final speeds of the spaceship, measured in meters.

If we know that v_{o} = 0\,\frac{m}{s}, v = 10968\,\frac{m}{s} and \Delta s = 212.8\,m, then the acceleration experimented by the spaceship is:

a = \frac{\left(10968\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (212.8\,m)}

a = 282652.782\,\frac{m}{s^{2}}

The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.

5 0
3 years ago
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