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3 years ago

Prove that f(x)=x+3/2 and g(x)=2x-3are inverse

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

5 0

Answer:

Proofs

Step-by-step explanation:

$f(x) = x + \frac{3}{2}$

$y = x + \frac{3}{2}$

$x = y + \frac{3}{2}$

$x - \frac{3}{2} = y$

${f}^{ - 1} (x) = x - \frac{3}{2}$

They are not inverse because f^-1(x) = x - 3/2 is not the inverse to g(x) = 2x - 3.

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279 is 33 1/2 of what amount

ycow [4]

Answer:

33% of 279 is equivalent to multiplying them: 33% × 279.

Step-by-step explanation:

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3 years ago

AB = 2x-5 BC = 6x AC = 27

OlgaM077 [116]

Answer:

correct answer is x = 2.75

Step-by-step explanation:

Given;

AB = 2x-5

BC = 6x

AC = 27

Hence,

=> AC = AB + BC

=> 27 = 2x-5 + 6x

=> 27 = 8x-5

=> 27-5 = 8x

=> 22 = 8x

=> 22/8 = x

=> 11/4 = x

2.75 = x

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2 years ago

Write the difference 16 -(-53) as a sum then simplify

valina [46]

Answer:

Step-by-step explanation:

(-)(-) = (+)

(+)(+) = (+)

(-)(+) = (+)(-) = (-)

--------------------------------------

16 - (-53) = 16 + 53 = 69

3 0

3 years ago

A pack of 8 batteries cost 4.72!What is cost per battery?

Mrrafil [7]

4.72 x 1 = 4.72
8 x X =8x
We need to let the X alone so
4.72 divided 8 = 0.59
1 battery = 0.59

8 0

2 years ago

Completing the square method sucks!!

slamgirl [31]

$\huge\underline\purple{Answer ☘}$

$4x {}^{2} + 3x + 5 = 0 \\ \\ dividing \: by \: 4... \\ \frac{4x {}^{2} }{4} + \frac{3x}{4} + \frac{5}{4} = 0 \\ x {}^{2} + \frac{3x}{4} + \frac{5}{4} = 0 \\ \\ we \: know \: that... \\ \: (a + b) {}^{2} = a {}^{2} + b {}^{2} + 2ab \\ \\ here... \\ 2ab = \frac{3x}{4} \\ = > 2xb = \frac{3x}{4} \: \: \: \: \: \: \: \: \: (a = x) \\ 2b = \frac{3}{4} \\ b = \frac{3}{4} \times \frac{1}{2} = \frac{3}{8}$

<h3>nσw ín σur єquαtíσn... </h3>

$x {}^{2} + \frac{3x}{4} + \frac{5}{4} = 0 \\ \\adding \: and \: subtracting \: (\frac{3}{8}){}^{2} \\ \\ x {}^{2} + \frac{3x}{4} + \frac{5}{4} + ( \frac{3}{8} ) {}^{2} { - ( \frac{3}{8} })^{2} = 0 \\ \\ x {}^{2} + \frac{3x}{4} + (\frac{3}{8} ) {}^{2} + \frac{5}{4} - ( \frac{3}{8} ) {}^{2} = 0 \\ \\ (x + \frac{3}{8} ) {}^{2} + \frac{5}{4 } - ( \frac{3}{8} ) {}^{2} = 0 \\ \\ (x + \frac{3}{8} ) {}^{2} = (\frac{3}{8} ) {}^{2} - \frac{5}{4} \\ \\ (x + \frac{3}{8} ) {}^{2} = \frac{9}{64} - \frac{5}{4} \\ \\ (x + \frac{3}{8} ) {}^{2} = \frac{9 - 5(16)}{64} \\ \\ (x + \frac{3}{8} ) {}^{2} = \frac{9 - 80}{64} \\ \\ (x + \frac{3}{8} ) {}^{2} = \frac{ - 71}{64}$

<h3>ѕíncє.. </h3>

ѕquαrє σf αnч numвєr cαn't вє nєgαtívє..

ѕσ.. αnѕwєr dσєѕ nσt єхíѕt~

hσpє hєlpful~

<h2>~Be Brainly!</h2>

3 0

2 years ago