Answer:
, 
, 
, 
, 
Explanation:
Empirical formula of the compound is the simplest ratio of elements present in the compound.
Empirical formula of compounds of chlorine with oxygen is as follows:
Compounds in which oxidation state of Cl is +1
Compounds in which oxidation state of Cl is +3
Compounds in which oxidation state of Cl is +4
Compounds in which oxidation state of Cl is +6
Compounds in which oxidation state of Cl is +7
Answer:
It keeps us alive, helps us grow plants, helps plants thrive, gives us food, helps keep our animals and crops healthy, cleans us, and so much more
Explanation:
Answer:
1. 7.256g of NaCl
2. 47.33g of Cl2
Explanation:
2 moles of Na reacts to produce 2 moles of NaCl
8 moles of Na will still produce 8 moles of NaCl
Mass of NaCl = molar mass of Nacl/moles of Nacl
=58.5/8
=7.256g of NaCl
From the equation, 2 moles of Na reacts with 1 mole of Cl2
3/2 moles of Cl2 will react with 3 moles of Na
Mass of Cl2 = 71/1.5
=47.33g of Cl2
Answer:
1.514 moles
Explanation:
For this problem you want to use dimensional analysis and cancel out your molecules of sugar and be left with moles of sugar. We know that 1 mole (of anything) = 6.022 x 10 ^ 23 molecules, so we should use that conversion to help us. Start with 9.12 x 10 ^23 molecules and divide by 6.022 x 10 ^ 23 molecules, and you will be left with moles.
Hope this helps!
