Momentum is one of those things that are 'conserved' (like energy). That means the total amount of momentum in an isolated system is the same after some event as it was before the event.
Before the ear-splitting explosion, while the firecracker and the billiard balls were just sitting there on the frictionless table, the momentum of the system was zero, because nothing was moving. Right there, that tells us that the total momentum of all the balls and the fragments of the firecracker ... if you add up all the momentum vectors AFTER the explosion ... the sum is still zero. (D)
Answer:
<em>The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.</em>
Explanation:
<u>Mechanical Force</u>
The second Newton's law states the net force exerted by an external agent on an object of mass m is:
Where is the acceleration of the object. Note both the force and the acceleration are vectors. The relationship between them is the mass, a scalar.
This means the net force and the acceleration have the same direction.
The sailboat has a mass m= 350 Kg and moves at a=0.62 m/s^2. The magnitude of the net force acting on the boat is:
As stated above its direction is the same as the acceleration, thus:
The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.
Answer:
The age of the rock is years
Explanation:
We can write the formula for the quantity of material in an exponential decay as:
where is the initial quantity of the material, and is the mean lifetime of the material.
This means that the total material that has decayed is:
The mean lifetime can be obtained from the half-life ( ) by the relationship
For our problem, as there was no Sr-87 present in the rock initially, and its a product of the decay, its abundance will be given by , this means, the total quantity of material that has decayed.
So, our equation for the ratio will be
Working it a little
The half-life of the problem is
So, the age of the rock will be
The pressure reading for the butane tank is higher than that for the propane tank is False.
The pressure readings will change when more liquid is added to the tanks is False.
If the tanks are placed outside and the sun warms each tank to 46 , the pressure readings will be higher than they were initially is True
If an equal number of moles of gas is allowed to escape rapidly from each tank, the temperature of the butane tank will be lower than that of the propane tank is True.
This question is incomplete, the complete question is;
The Figure shows a container that is sealed at the top by a moveable piston, Inside the container is an ideal gas at 1.00 atm. 20.0°C and 1.00 L.
"What will the pressure inside the container become if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant?"
Answer:
the pressure inside the container become 0.625 atm if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant
Explanation:
Given that;
P₁ = 1.00 atm
P₂ = ?
V₁ = 1 L
V₂ = 1.60 L
the temperature of the gas is kept constant
we know that;
P₁V₁ = P₂V₂
so we substitute
1 × 1 = P₂ × 1.60
P₂ = 1 / 1.60
P₂ = 0.625 atm
Therefore the pressure inside the container become 0.625 atm if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant