When does radioactivity decay occur?

Hurry help please, number 3

Dovator [93]

C most of the Earths weather occurs in this layer.

6 0

3 years ago

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12 seconds after starting from rest a frewly falling cantaloupe has a speed of

adoni [48]

Answer:

<em>The cantaloupe has a speed of 117.6 m/s</em>

Explanation:

<u>Free Fall Motion</u>

It occurs when an object falls under the sole influence of gravity. Any object that is being acted upon solely by the force of gravity is said to be in a state of free fall. Free-falling objects do not face air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is $g = 9.8 m/s^2$ .

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The cantaloupe has been dropped from rest. We are required to find the speed after t=12 seconds.

Calculate the final speed:

vf=9.8 * 12 = 117.6 m/s

The cantaloupe has a speed of 117.6 m/s

3 0

3 years ago

A 0.017 g coin sliding to the right at 0.255 m/s makes an elastic head-on collision with a 0.040 g coin that is initially at res

zysi [14]

Answer:

$\approx 0.154\:\mathrm{m/s}$

Explanation:

In all collisions, whether elastic or inelastic, momentum must be conserved. Therefore, we can write an equation using the conservation of momentum:

$m_{c1}v_{c1,i}+m_{c2}v_{c2,i}=m_{c1}v_{c1,f}+m_{c2}v_{c2,f}$

Solving for $v_{2c,f}$ :

$0.000017\cdot 0.255+0.000040\cdot0=0.000017\cdot (-0.108)+0.000040\cdot v_{c2,f},\\v_{c2,f}\approx \boxed{0.154\:\mathrm{m/s}}$

*Notes:

-It's important to convert g to kg, as kg is the SI unit of mass

-The negative sign in a velocity measure represents direction

-Since the velocity we solved for is positive, it implies that the direction is to the right

5 0

3 years ago

A charge q moves from point A to point B in an electric field. The potential energy of the charge at point A is 5.6 × 10-10 joul

Ierofanga [76]

From your choices which are
A. 5.6 × 10-12 joules
B. 1.3 × 10-12 joules
C. 2.3 × 10-12 joules
D. 3.3 × 10-10 joules
E. 5.6 × 10-10 joules

The answer is 3.3 × 10-10 joules. The answer is letter c.

7 0

3 years ago

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Although 0 dB is often referred to as the lower threshold of human hearing, it is important to realize that the human ear is not

IRISSAK [1]

Answer:

20 Hz

15.8 times

Explanation:

A

Although the range of frequency for any human's ear is usually said to be between 20 Hz and 20 kHz. And since the question asked for the least intense frequency, that has to be 20 Hz. Essentially the frequency most people perceive the least intense sound is 20 Hz.

B

A 100-Hz sound must be 10^1.2 times or 15.8 times more intense compared to a 1000-Hz sound to be perceived as equal to 60 phons of loudness

5 0

3 years ago