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Mashcka [7]
3 years ago
9

If two students push a box with a force of 3N in the same direction, and there is no other unbalanced force on the box, what is

the magnitude of the net force on the box? *
0N
3N
6N
9N
Physics
2 answers:
FrozenT [24]3 years ago
6 0
It’s 9N because unbalanced force on the box
dimulka [17.4K]3 years ago
5 0

Answer:

SILEM B

Explanation:

ERILAQNQJJQKIQKQJNDJKIDJKS

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Answer:

Explanation:

The y component is measured by the horizontal component and the vertical component. Together they determine the magnitude of the vector. In this case, the y or vertical component is found by using the sine function.

<em>Formula</em>

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The vector is pointing downward so technically the vertical component should be negative.  I'm not sure what to tell you to answer. I would try - 280.37, but if the computer marks you wrong, try 280.37 (no minus sign).

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