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Brums [2.3K]
3 years ago
7

Find the volume of a solid

Mathematics
1 answer:
fredd [130]3 years ago
4 0

Answer:Volume = Area of the base × height

Step-by-step explanation:

If the rectangular box were filled with 1 cm cubes, there would be:

6 × 2 cubes in the bottom layer

As there are 3 layers,

Volume = 36 cubic centimetres

Now note that the area of the box's base is given by:

Area = 12 square centimetres

From the above discussion, we can derive a formula for the volume of a rectangular box as follows:

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The formula for a sequence or series used to find any term in that sequence or series
ANTONII [103]

Step-by-step explanation:

Tn = a + (n - 1) d

Where

Tn is the nth term of the sequence

a is the first term of the sequence

n is the number/term of the sequence to be solved

d is the common difference

6 0
3 years ago
In ΔLMN, m = 390 cm, n = 430 cm and ∠L=134°. Find the length of l, to the nearest centimeter. PLEASE HELP ITS URGENT
BartSMP [9]

Answer:

755

Step-by-step explanation:

DeltaMath

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3 years ago
The sum of two numbers is 25. Their difference is 9. What are the two numbers?
Lynna [10]
Using x and y as the numbers

x+y=25 -------#1
x-y=9  -------#2

Using addition of #1 and #2
x+y+x-y= 25+9
2x+0y=34
2x=34
x=17

Using the value of x and plugging said value into #1 or #2, we can find y
x=17

x+y=25
17+y=25
y=8

OR

x-y=9
17-y=9
-y=-8
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The numbers are 8 and 17
5 0
3 years ago
Read 2 more answers
You recently took a statistics exam in a large class. The instructor tells the class that the scores were Normally distributed,
Lunna [17]

Answer:

b. the area to the right of 2

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the area to the left of Z. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to the right of Z.

In this problem:

X = 96, \mu = 72, \sigma = 12

Z = \frac{X - \mu}{\sigma}

Z = \frac{96 - 72}{12}

Z = 2

Percentage who did better:

P(Z > 2), which is the area to the right of 2.

5 0
3 years ago
What is the answer please help!
Sav [38]

Answer:

(1,3)

Step-by-step explanation:

8 0
3 years ago
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