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aleksley [76]
3 years ago
15

even after being stirred a solution has solute crystals at the bottom. if the temperature remains constant what happens when mor

e solute is added to the solution
Chemistry
1 answer:
icang [17]3 years ago
7 0

Answer:

It becomes a supersaturated solution

Explanation:

Due to the fact that the crystals can no longer dissolve and adding more solute to the same temperature will continue not to dissolve the crystals making it more and more saturated leading to supersaturated solution

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Atoms are never rearranged
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Damian mixed two samples together: a
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Type of reaction<br> PbSO. →<br> PbSO3 + __02<br> Type of reaction:
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If cells did not work together what would happen to the organisms
arlik [135]

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5 0
1 year ago
In a lab experiment 80.0 g of ammonia [NH3] and 120 g of oxygen are placed in a reaction vessel. At the end of the reaction 72.2
valentinak56 [21]

The percent yield of the reaction : 89.14%

<h3>Further explanation</h3>

Reaction of Ammonia and Oxygen in a lab :

<em>4 NH₃ (g) + 5 O₂ (g) ⇒ 4 NO(g)+ 6 H₂O(g)</em>

mass NH₃ = 80 g

mol NH₃ (MW=17 g/mol):

\dfrac{80}{17}=4.706

mass O₂ = 120 g

mol O₂(MW=32 g/mol) :

\tt \dfrac{120}{32}=3.75

Mol ratio of reactants(to find limiting reatants) :

\tt \dfrac{4.706}{4}\div \dfrac{3.75}{5}=1.1765\div 0.75\rightarrow O_2~limiting~reactant(smaller~ratio)

mol of H₂O based on O₂ as limiting reactants :

mol H₂O :

\tt \dfrac{6}{5}\times 3.75=4.5

mass H₂O :

4.5 x 18 g/mol = 81 g

The percent yield :

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{72.2}{81}\times 100\%=89.14\%

6 0
3 years ago
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