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3 years ago

What size container is needed to hold 7.00 mol of a gas at 342 K and 255 kPa? *

1 answer:

3 0

PV = nRT

I only know the valeu of R is you're using atm, so convert kPa to atm.

1 atm = 101.325 kPa

2.52 atm = 255 kPa

2.52atm(x) = 7(.0821)(342)

2.52atm(x) = 196.5

x = 78

78 liters

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The work function is the energy that must be supplied to cause the release of an electron from a photoelectric material. The cor

vladimir2022 [97]

Answer:

No photoelectric effect is observed for Mercury.

Explanation:

From E= hf

h= Plank's constant

f= frequency of incident light

Threshold Frequency of mercury= 435×10^3/ 6.6×10^-34 × 6.02×10^23

f= 11×10^14 Hz

The highest frequency of visible light is 7.5×10^14. This is clearly less than the threshold frequency of mercury hence no electron is emitted from the mercury surface

3 0

4 years ago

How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?

Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

$C_{6}H_{8}O_{6}$

Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.

We have that:

$C_{6}=12.0107g*6=72.08g\\\\H_{8}=1.008g*8=8.064g\\\\O_{6}=15.999g*6=95.994g\\\\C_{6}H_{8}O_{6}=72.08g+8.064g+95.994g=176.138g$

To know the percent of each element, we need to to the following:

$C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)$

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

$C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}$

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

$C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol$

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

5 0

3 years ago

A container holds 15.0 g of phosphorous gas at a pressure of 2.0 atm and a temperature of 20.0 Celsius. What is the density of t

erik [133]

Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We calculate as follows:

PV = nRT
PV = mRT/ Molar mass
m/V = P(molar mass)/RT
Density = P(molar mass)/RT
Density = 2.0 ( 30.97 ) / 0.08206 ( 20 + 273.15) = 2.57 g/L <----First option

5 0

3 years ago

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A standard drink of beer is _ ounces.

kiruha [24]

A standard drink of beer is 12 ounces

4 0

3 years ago

Read 2 more answers

Study the graph in Figure 6.32 and answer to these questions. (see attached image)

Dimas [21]

Hey there :)

We can see that the solubility of salt increases with increasing temperature. This happens with most substances.

To find out the maximum mass of copper sulfate that can be dissolved in water at these temperatures, just interpret the graph.

Considering Y-axis as g copper sulfate/100 g water and the X-axis as the temperature in °C:-

1)

a: 0 °C - 14 g of copper sulfate/100 g of water

b: 50 °C - 34 g of copper sulfate/100 g of water

c: 90 °C - 66 g of copper sulfate/100 g of water

2) From the graph, we can infer that temperature affects the solubility of the salt.

Answered by Benjemin360 :)

3 0

2 years ago