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igor_vitrenko [27]
3 years ago
6

What size container is needed to hold 7.00 mol of a gas at 342 K and 255 kPa? *

Chemistry
1 answer:
ValentinkaMS [17]3 years ago
3 0
PV = nRT

I only know the valeu of R is you're using atm, so convert kPa to atm.

1 atm = 101.325 kPa

2.52 atm = 255 kPa

2.52atm(x) = 7(.0821)(342)

2.52atm(x) = 196.5

x = 78

78 liters

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Consider the relationship (y+3)2 = b/(x-2), where y and x are variables and bis a constant. On rectangular coordinate paper, wha
Nikolay [14]

Answer:

(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.

Explanation:

\frac{(y+3)}{2} = \frac{b}{(x-2)}

Taking natural logarithm on both the sides:

\ln [(y+3)]-\ln[2]=\ln [b]-\ln [(x-2)]

\ln [(y+3)]=\ln[2]+\ln [b]-\ln [(x-2)]

\ln [(y+3)]=\ln {[2\times b]-\ln [(x-2)]

Slope intercept form is generally given as:

y=mx+c

m = slope, c  = intercept on y axis or vertical axis

On rearranging equation:

\ln [(y+3)]=(-1)\times \ln [(x-2)]+\ln {2b}

y = ln [(y+3)], x = ln [(x-2)], m=-1 , c  = ln 2b

(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.

8 0
3 years ago
Calculate the mass of liquid with density of 3.3 g/mL and a volume of 25 oz
love history [14]

Answer: 215

Explanation:

Volume doesn’t add up into ounces that’s mass only

3 0
3 years ago
If the density of mercury is 13.6g/ml, how many ml of mercury are in 1,000 g of mercury?
Illusion [34]

Answer:

<h2>73.53 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question we have

volume =  \frac{1000}{13.6}  \\  = 73.52941...

We have the final answer as

<h3>73.53 mL</h3>

Hope this helps you

6 0
3 years ago
A chemical equation does not give information about what
Lana71 [14]

A chemical equation does not give information about the following:

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  • The "speed of the reaction" is not mentioned.
  • The "concentration of the substance" whether it is diluted or concentrated is not mentioned.
  • The "rate of the reaction", temperature, catalyst, pressure etc is not mentioned. These can be mentioned "above or below the arrow".

8 0
3 years ago
This is the balances equations. C3H8 + 5O2 → 3CO2 + 4H2O How many moles of oxygen are required to produce 37.15 g CO2
AleksandrR [38]
Molar mass O2 = 31.99 g/mol

Molar mass CO2 = 44.01 g/mol

Moles ratio:

<span>C3H8 + 5 O2 = 3 CO2 + 4 H2O 
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mass of O2 = 37.15 x 5 x 44.01/ 3 x 44.01

mass of O2 = 8174.8575 / 132.03

mass of O2 = 61.916 g 

Therefore:

1 mole O2 ----------------- 31.99 g
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moles O2 = 61.916 x 1 / 31.99

moles = 61.916 / 31.99 => 1.935 moles of O2
4 0
3 years ago
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