OD.......................
1. c
2. a
3. a
(I’m not 100% but 2 & 3 couldn’t be transform)
Chemical symbols are represented with their coefficients in a balanced reaction. Ethane and oxygen are the reactants, whereas carbon monoxide and water are the products.
4 HCl (g) + O₂ (g) → 2 Cl₂ (g) + 2 H₂O (l)
<h3>What is Carbon monoxide?</h3>
Carbon monoxide, a colorless, incredibly lethal, odorless, tasteless, and flammable gas with the chemical formula CO, is a little less dense than air. Carbon monoxide is a compound made composed of one carbon atom and one oxygen atom joined by three bonds. This is the simplest molecule in the oxocarbon family. The term "carbonyl" refers to the carbon monoxide ligand in coordination complexes. It is an essential part of many industrial chemistry procedures.
Carbon monoxide plays important biological roles in all phylogenetic kingdoms.
To learn more about Carbon monoxide from the given link:
brainly.com/question/10193078
#SPJ4
Answer:
1) Ethane is the limiting reactant
2) mass of CO₂ produced is 733.33 g
Explanation:
C₂H₆ + 2O₂ → 2CO₂ + 3H₂ ------------------------(1)
molar ratio for equation (1) can be shown as;
1 : 2 → 2 : 3
molecular weight of moles of C₂H₆ = 30 g/mol
molecular weight of moles of O₂ = 32 g/mol
molecular weight of moles of CO₂ = 44 g/mol
mass of O₂ = 220 g
mass of C₂H₆ = 250 g
number of moles of O₂ = mass ÷ molecular weight = 220 g ÷ 32 g/mol * 2 = 13.75 moles
number of moles of C₂H₆ = mass ÷ molecular weight = 250 g ÷ 30 g/mol = 8.333 moles
1) Ethane is the limiting reactant as the 8.333 moles will finish before the 13.75 moles of the oxygen is totally consumed.
2) 1 mole of C₂H₆ will form 2 moles of CO₂
Therefore, 8.333 moles will form 16.667 moles of CO₂
mass of CO₂ formed = number of moles * molecular weight = 16.667 * 44 = 733.33 g
Answer:
1.68 atm
Explanation:
Applying
P/T = P'/T'................... Equation 1
Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T' = Final Temperature.
Make P' The subject of the equation
P' = PT'/T.............. Equation 2
From the question,
Given: P = 2.25 atm, T = 125°C = (125+273) K = 398 K, T' = 25°C = (25+273) K = 298 K.
Substitute these values into equation 2
P' = (2.25×298)/398
P' = 1.68 atm
