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swat32
3 years ago
14

In a separate location, take notes from the sources you’ve identified. The notes will provide details for your paper. While taki

ng notes, you may want to use these reading strategies. Use these sources if you find them helpful: Using your notes, compare the features of analog and digital signals in the table provided. Include one to three points for each feature and type of signal.

Chemistry
1 answer:
NARA [144]3 years ago
6 0

Answer:

Here is every answer for analog and digital (in order)

Analog:

  • Signal Shape: Smooth and continuous
  • Numerical Values for Signal Measurements: Analog signals represent one continuous variable as the result of another continuous time-based variable. They are capable of outputting continuous information with a theoretically infinite number of possible values.
  • Amount of Data that can be transmitted: analog circuits can conduct only fairly low-speed data communications. The maximum data rate over an analog facility is 33.6K bps when there are analog loops at either end. With 56K bps modems, only one end of the loop can be analog. The other end of the connection has to be digital.
  • Energy requirements: light, sound, temperature, position, and pressure
  • Privacy and security (ability of the signal to be encoded in a secret code): not encrypted
  • Clarity of Signal: noise affects clarity and quality, noise is amplified, amplified noise causes more random information in the signal, signal bandwidth is low

Digital (in order):

  • Signal shape: stepping, square, and discrete
  • Numerical Values for Signal Measurements: digital communication methods transmit a complete measured value, in other words both a numeric value and a unit of measurement
  • Amount of data that can be transmitted: First of all, it is theoretically possible to transmit digital signals directly. Unfortunately when we use capacitors and inductors (energy storage devices) to match the impedance from the transmitter to the air (low impedance transistor say 5 ohms to 388 ohms (air)) these components introduce a bandwidth limiting match. Since all impulse functions have infinite bandwidth (transmitting a 1 and a zero) the bandwidth of the transceiver must be multi octave in order to have any reasonable efficiency. Systems engineers simplify the problem by introducing direct sequence modulation where a carrier is modulated 0/180 degrees dependent on the data rate.
  • Energy requirements: voltage, accoustic pressure, and magnetization of a magnetic storage media
  • Privacy and security: encrypted
  • Clarity of signal: noise is lower in amplitude, electronics can ignore the noise, quality of signal is maintained, signal is high

Explanation:

I did mine in bullet points, hopefully this helped!

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lana66690 [7]

1. C

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4. Normal faults are faults where the hanging wall moves in a downward force based on the footwall; they are formed from tensional stresses and the stretching of the crust. Reverse faults are the opposite and the hanging wall moves in an upward force based on the footwall; they are formed by compressional stresses and the contraction of the crust.  Thrust faults are low-angle reverse faults where the hanging wall moves in an upward force based on the footwall; they are formed in the same way as reverse faults. Last, Strike-slip faults are faults where the movement is parallel to the crust of the fault; they are caused by an immense shear stress. 


I hope this helped :D

7 0
3 years ago
Quantum transitions that result in the characteristic sharp lines of the X-ray spectrum always involve
labwork [276]

Answer: 5

Explanation: this is because the energy level of the emitted of absorbed photon increases as the number of electron shell decreases, thereby making the inner shell have higher energy than other shells

4 0
3 years ago
Predict the missing product of this equation<br><br><br>1 MgF2 + 1 Li2CO3 -&gt; 1 ______ +2LiF
ch4aika [34]

Answer:

MgCO₃

Explanation:

From the question given above, we obtained:

MgF₂ + Li₂CO₃ —> __ + 2LiF

The missing part of the equation can be obtained by writing the ionic equation for the reaction between MgF₂ and Li₂CO₃. This is illustrated below:

MgF₂ (aq) —> Mg²⁺ + 2F¯

Li₂CO₃ (aq) —> 2Li⁺ + CO₃²¯

MgF₂ + Li₂CO₃ —>

Mg²⁺ + 2F¯ + 2Li⁺ + CO₃²¯ —> Mg²⁺CO₃²¯ + 2Li⁺F¯

MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF

Now, we share compare the above equation with the one given in the question above to obtain the missing part. This is illustrated below:

MgF₂ + Li₂CO₃ —> __ + 2LiF

MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF

Therefore, the missing part of the equation is MgCO₃

8 0
3 years ago
What is an extinct species? *
pentagon [3]

Answer: C

Explanation: I got it right.

8 0
3 years ago
What is the percent yield of nacl if 31.0 g of cucl2 reacts with excess nano3 to produce 21.2 g of nacl?
Free_Kalibri [48]
Hope this helps you.

8 0
3 years ago
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