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swat32
3 years ago
14

In a separate location, take notes from the sources you’ve identified. The notes will provide details for your paper. While taki

ng notes, you may want to use these reading strategies. Use these sources if you find them helpful: Using your notes, compare the features of analog and digital signals in the table provided. Include one to three points for each feature and type of signal.

Chemistry
1 answer:
NARA [144]3 years ago
6 0

Answer:

Here is every answer for analog and digital (in order)

Analog:

  • Signal Shape: Smooth and continuous
  • Numerical Values for Signal Measurements: Analog signals represent one continuous variable as the result of another continuous time-based variable. They are capable of outputting continuous information with a theoretically infinite number of possible values.
  • Amount of Data that can be transmitted: analog circuits can conduct only fairly low-speed data communications. The maximum data rate over an analog facility is 33.6K bps when there are analog loops at either end. With 56K bps modems, only one end of the loop can be analog. The other end of the connection has to be digital.
  • Energy requirements: light, sound, temperature, position, and pressure
  • Privacy and security (ability of the signal to be encoded in a secret code): not encrypted
  • Clarity of Signal: noise affects clarity and quality, noise is amplified, amplified noise causes more random information in the signal, signal bandwidth is low

Digital (in order):

  • Signal shape: stepping, square, and discrete
  • Numerical Values for Signal Measurements: digital communication methods transmit a complete measured value, in other words both a numeric value and a unit of measurement
  • Amount of data that can be transmitted: First of all, it is theoretically possible to transmit digital signals directly. Unfortunately when we use capacitors and inductors (energy storage devices) to match the impedance from the transmitter to the air (low impedance transistor say 5 ohms to 388 ohms (air)) these components introduce a bandwidth limiting match. Since all impulse functions have infinite bandwidth (transmitting a 1 and a zero) the bandwidth of the transceiver must be multi octave in order to have any reasonable efficiency. Systems engineers simplify the problem by introducing direct sequence modulation where a carrier is modulated 0/180 degrees dependent on the data rate.
  • Energy requirements: voltage, accoustic pressure, and magnetization of a magnetic storage media
  • Privacy and security: encrypted
  • Clarity of signal: noise is lower in amplitude, electronics can ignore the noise, quality of signal is maintained, signal is high

Explanation:

I did mine in bullet points, hopefully this helped!

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7. Disulfur dichloride can be made by reacting chlorine gas with molten sulfur. What is the yield of S2Cl2 expected in a laborat
Pie

Answer:

11.4g of S₂Cl₂ is the expected yield

9.69g of S₂Cl₂ are produced with a 85% yield

Explanation:

The reaction of sulfur S₈ with Cl₂ to produce S₂Cl₂ is:

S₈ + 4Cl₂ → 4S₂Cl₂

<em>Where 1 mole of sulfur reacts with four moles of chlorine to produce four moles of disulfur dichloride.</em>

To find the limiting reactant you need to convert mass of each reactant to moles using its molar mass, thus:

S₈ (Molar mass: 256.52g/mol): 10.0g ₓ (1mol / 256.52g) = 0.0390 moles S₈

Cl₂ (Molar mass: 70.9g/mol): 6.00g ₓ (1mol / 70.9g) = 0.0846 moles Cl₂

For a complete reaction of 0.0390 moles of sulfur, there are necessaries:

0.0390 mol S₈ ₓ (4 mol Cl₂ / 1 mol S₈) = <em>0.156 moles Cl₂. </em>As you have just 0.0846 moles of chlorine, Cl₂ is the limiting reactant.

As 4 moles of Cl₂ produce 4 moles of S₂Cl₂.<em> 0.0846 moles of Cl₂ produce, in theory, 0.0846 moles of S₂Cl₂ (Molar mass: 135.04g/mol). </em>In mass:

0.0846 moles S₂Cl₂ ₓ (135.04g/mol) =

<h3>11.4g of S₂Cl₂ is the expected yield</h3>

If you produce just the 85.0% of yield, mass of S₂Cl₂ is:

11.4g ₓ 85% =

<h3>9.69g of S₂Cl₂</h3>
3 0
3 years ago
What is the general formula for a secondary amine? rnh2 h2nrnh2 rn2h r2nh
zvonat [6]

The general fomula of the amine group ought to be R2NH because, the two hydrogen atoms of ammonia have been substituted by alkyl groups.

<h3>What is a secondary amine?</h3>

A secondary amine is one in which two alkyl groups are subtituted on the nitrohen atom of ammonia.

This implies that the general fomula of the amine group ought to be R2NH. This is because, the two hydrogen atoms of ammonia have been substituted by alkyl groups.

Learn more about secondary amine: brainly.com/question/12682525

4 0
2 years ago
Boyle's Law expresses the pressure-volume
Colt1911 [192]

Answer:

\large \boxed{\text{175. atm}}

Explanation:

Data:

p₁ = 1.00 atm; V₁ = 350.      L

p₂ = ?;             V₂ =     2.00 L

Calculation:

\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{1.00 atm} \times \text{350. L} & = & p_{2} \times\text{2.00 L}\\\text{350. atm} & = & 2.00p_{2}\\p_{2} & = & \dfrac{\text{350. atm}}{2.00}\\\\& = &\textbf{175. atm}\\\end{array}\\\text{It would take a pressure of $\large \boxed{\textbf{175. atm}}$ to compress the gas.}

8 0
3 years ago
please help, ive been putting 3 for the coefficient and 14 for the exponent but, it keeps saying it’s wrong. any help is appreci
ELEN [110]

Answer:

3 × 10¯¹⁰

Explanation:

9×10² ÷ 3×10¹²

The above expression can be evaluated as follow:

9×10² ÷ 3×10¹²

Recall:

3² = 9

3¹ = 3

Therefore,

9×10² ÷ 3×10¹² = 3²×10² ÷ 3¹×10¹²

Recall:

y^m ÷ y^n = y^(m – n)

Therefore,

3²×10² ÷ 3×10¹² = 3²¯¹ × 10²¯¹²

= 3¹ × 10¯¹⁰

Recall:

y¹ = y

Therefore,

3¹ × 10¯¹⁰ = 3 × 10¯¹⁰

Therefore,

9×10² ÷ 3×10¹² = 3 × 10¯¹⁰

6 0
3 years ago
Has no definite shape, does not take up a definite<br> amount of space.
MAXImum [283]

gas.

hope it helps......

7 0
3 years ago
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