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Masja [62]
3 years ago
13

Look at the sceenshot-- help??

Mathematics
1 answer:
Burka [1]3 years ago
4 0
The answer is: 3.
_________________
In the table, the relation (x, y) is not a function is the "missing value" of "x" is: 3.
_______________________________________
Explanation: We are given that the ordered pair: "(3,10)" exists.  In other words, when x = 3, y =10. 
______________________________________
The "missing value" refers to the "empty box" in the table shown (in the attached screenshot).  The "empty box" shows a "y-coordinate" of "20"; but a "missing" corresponding "x-coordinate".
____________________________________
The problem asks: 
_________________
In the table, the relation (x, y) is not a function is the "missing value" of "x" is: ____?
___________________
The answer is: 3.
_______________________
We know the answer is "3"; because we know that "3" already has 1 (one) corresponding y-coordinate.

By definition, a "function" cannot have ANY "x-coordinates" that have more than one "corresponding y-coordinate".   As such:
_______________________________________
In the table, the relation (x, y) is not a function is the "missing value" of "x" is:
____________
3.
____________
Additional information:
____________
When examining an equation on an actual graph, we can use what is called the "vertical line test".  That is, one can take a pencil and vertically go through the "y-axis", or even examine it visually, to see if there are any "x-values" that have more than one corresponding "y-coordinate".
   If no, then it "passes" the "vertical line test" and is a "function".  
If not, then it does NOT pass the "vertical line test" and is NOT a function.
__________________________________________
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The answer is 15

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PLEASE HELP!! Anyone??
klasskru [66]
Replace P with 15:

d = -3(15)^2 + 168(15) - 315

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3 0
3 years ago
Multiply 13.4x0.05x1.8=
jek_recluse [69]

13.4 x 0.05 = 0.67

0.67 x 1.8 = 1.206

So the answer if 1.206

3 0
4 years ago
h(t)=(t+3) 2 +5 h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plu
lesya692 [45]

Answer:

1

Step-by-step explanation:

If I understand the question right, G(t) = -((t-1)^2) + 5 and we want to solve for the average rate of change over the interval −4 ≤ t ≤ 5.

A function for the rate of change of G(t) is given by G'(t).

G'(t) = d/dt(-((t-1)^2) + 5). We solve this by using the chain rule.

d/dt(-((t-1)^2) + 5) = d/dt(-((t-1)^2)) + d/dt(5) = -2(t-1)*d/dt(t-`1) + 0 = (-2t + 2)*1 = -2t + 2

G'(t) = -2t + 2

This is a linear equation, and the average value of a linear equation f(x) over a range can be found by (f(min) + f(max))/2.

So the average value of G'(t) over −4 ≤ t ≤ 5 is given by ((-2(-4) + 2) + (-2(5) + 2))/2 = ((8 + 2) + (-10 + 2))/2 = (10 - 8)/2 = 2/2 = 1

Click to let others know, how helpful is it

3 0
4 years ago
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