These are 2 questions and 2 answers:
<span>1.
Question 1: The area of a rectangular carpet is given by the trinomial 5x^2 - 3x -
14. What are the possible dimensions of the carpet? Use factoring.
Answer: 5x^2 -3x -14
Explanation:
You might probe the different pairs of factors given in the answer choices to check wich product is equal to the oirginal polynomial or you can factor from zero.
I will show you how to factor that polynomial from zero:
1) given: 5x^2 - 3x - 14
2) multiply and divide by the leading coefficient =>
5 [5x^2 - 3x -14 ]
----------------------
5
3) Enter the the factor 5 inside the parenthesis:
5.5x^2 - 5.3x - 5.14
--------------------------
5
4) rearrange conviniently to show (5x) as a common factir of the first two terms
(5x)^2 - 3(5x) - 70
--------------------------
5
5) factor the numerator using 5x as common term of the two binomials:
(5x ) ( 5x ) <----> open the parenthesis
(5x - ) (5x + ) <-----> include the signs
(5x - 10) (5x + 7) <---> two numbers that add up - 3 and their product is - 70
=>
(5x - 10)(5x + 7)
---------------------
5
6) divide (5x - 10) by 5 => x - 2
7) factored expression
(x - 2) (5x + 7)
8) Conclusion: the answer is the option B. (5x + 7) and (x - 2)
2. Question 2. The area of a rectangular barnyard is given by the trinomial 6x^2 +
7x – 20. What are the possible dimensions of the barnyard? Use factoring
Answer: </span><span><span>option C. (2x + 5)(3x - 4)</span>
Explanation:
The procedure is the same of the question 1.
1) given: 6x^2 + 7x - 20
2) multiply numerator and denominator by 6 and rearrange to show (6x) as common factor ot the first two terms =>
(6x)^2 + 7(6x) - 120
--------------------------
6
3) factor the numerador using 6x as common factor ot two binomials, and simplify:
(6x + )(6x - )
(6x + )(6x - )
(6x + 15) (6x - 8)
=>
(6x + 15)(6x -8)
---------------------
6
(6x + 15)(6x - 8)
---------------------- =
3.2
(6x + 15) (6x - 8)
------------- . ------------ =
3 2
(2x + 5)(3x - 4)
4) answer: option C. (2x + 5)(3x - 4)</span>
Answer:
Step-by-step explanation:
(x-1)²+(y+1)²=41
Given side length "a" and angle "A", calculate the diagonals<span><span>
p = square root [( 2a^2 - 2a^2 cos(A) )]
</span>q = </span><span>square root [( 2a^2+ 2a^2 cos(A) )]</span>
http://www.calculatorsoup.com/calculators/geometry-plane/rhombus.php
side = 36
cos (32) = 0.84805
p = <span>small diagonal = </span>
<span>
<span>
<span>
19.8457652914
</span>
</span>
</span>
<span><span>
</span>
</span>
q =
large diagonal =
<span>
<span>
<span>
69.2108777578
</span>
</span>
</span>
68
Explanation:
So to get this answer you need to split it into smaller shapes. We already have the squares so we know that 3*3 is 9 and then we double that because there are two of them.
So, so far we have 18+x
We need to take the middle shape and split it into two trapezoids.
The area for trapezoids is T=(a+b/2)h
So T= (3+7/2)5
T= 5*5=25
And then we would double that because there are two of them so 50 and then fill it in for x
18+50= 68 is the area of the figure.
