25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
8.25 hrs
Step-by-step explanation:
it takes 3/4 to replace all tires in a car
you then multiply 3/4 by 11
Hello,
the first step should be to distribue:
-4(3-5x)= -12+20x
Teh resolution may be:
-4(3-5x)>=-6x+9
==>-12+20x>=-6x+9
==>20x+6x>=9+12
==>26x>21
==>x>=21/26
But an other way may be used:
-4(3-5x)>=-6x+9
==>3-5x<= -6x/(-4)+9/(-4)
==>-5x-3/2 x<=-9/4 -3
==>-13/2 x <=-21/4
==>x>= -21/4 *(-2/13)
==>x>=21/(2*13)
==>x>=21/26
true if that's what ur looking for. hope this helps
Well, if that is a comma in the number, it is already rounded. If the comma is supposed to be a decimal, the answer would be $57.
