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raketka [301]
3 years ago
9

(4.6•10^9)+ (1.7•10^7)

Mathematics
1 answer:
Gennadij [26K]3 years ago
6 0

Answer:

4617000000

Step-by-step explanation:

10^9 = 1000000000

1000000000 x 4.6 = 4600000000

10^7 = 10000000

10000000 x 1.7 = 17000000

4600000000 + 17000000 = 4617000000

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Use long division to divide x^3+x^2-2x+14 by x+3
bekas [8.4K]

First, x^3=x^2\cdot x, and if we multiply x+3 by x^2 we get

x^3+3x^2

Subtracting this from the numerator gives a remainder of

-2x^2-2x+14

Next, -2x^2=-2x\cdot x, and if we multiply x+3 by -2x we have

-2x^2-6x

and subtracting this from the previous remainder, we end up with a new remainder of

4x+14

Next, 4x=4\cdot x, and if we multiply x+3 by 4 we get

4x+12

Subtracting from the previous remainder, we get a new remainder of

2

which contains no more factors of x, so we're done.

So,

\dfrac{x^3+x^2-2x+14}{x+3}=x^2-2x+4+\dfrac2{x+3}

8 0
3 years ago
A caterer has 5 rolls. He is ordering more rolls. He can order up to 9 packages of rolls and each package contains 12 rolls. The
stich3 [128]
B is the practical domain of the function

6 0
3 years ago
Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
viktelen [127]
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10                         
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
7 0
3 years ago
Find the area of a rectangle with a length of (8m³)² and a width of (4x²m⁴)
Alisiya [41]

Answer:nhnc

add it mc

Step-by-step explanation:vgnhc

7 0
3 years ago
PLZ HELP DONT get wrong have 10 min HELP
MAVERICK [17]

Answer:

5.5 7

Step-by-step explanation:

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3 years ago
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