Graph the image of the given triangle after the transformation with the rule (x, y)→(x+3, y−5) .
2 answers:
Graph the image of the given triangle after the transformation with the rule (x, y)→(x+3, y−5) .
The vertices of given triangle ABC is
A(2,2) B(7,3) and C(4,-3)
rule (x, y)→(x+3, y−5) , add 3 with x and subtract 5 from y.
A(2,2) becomes (2+3, 2-5) => (5,-3)
B(7,3) becomes (7+3, 3-5) => (10,-2)
C(4,-3) becomes (4+3, -3-5) => (7,-8)
So the vertices of triangle after transformation is
A'(5,-3) B'(10,-2) C' (7,-8)
The graph is attached below
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Answer:
Step-by-step explanation:
Given:
The equations given are:
Now, a linear function is of the form:
Where, 'm' and 'b' are real numbers and
Equation 1:
Simplifying using distributive property, we get:
The above equation is of the form . So, it represents a linear function.
Equation 2:
Here, both sides of the equation has same variable 'X'. So, it will form an equation of 1 variable. So, it's not a linear function.
Equation 3:
Simplifying the above equation. This gives,
This is not of the form of the linear function. So, it is also not a linear function.
Equation 4:
Simplifying the above equation. This gives,
This is not of the form of the linear function. So, it is also not a linear function.