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tino4ka555 [31]
3 years ago
5

HELP ASAP PLEASE PLEASE PLEASE Complete and balance the following reaction. Note that Cr forms +3 in the product. ____ Sn(NO3)2

(aq) + ____ Cr(s) → ____ _________ ( ) + ___ _________( ) b) How do the oxidation states of Sn and Cr change during the reaction? Sn changes from ___ to ____ and Cr changes from ____ to ____ c) Determine the net ionic equation including phases. d) Identify the oxidizing and reducing agents (give formula of compound, ion or element): OA = _____ RA = _____ e) Write the oxidation half rxn.

Chemistry
1 answer:
Rzqust [24]3 years ago
5 0

Answer:

Explanation:

3Sn(NO3)2 (aq) +  2Cr(s) → 2Cr(NO3)3(aq ) + 3Sn(S )

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These statements describe three different reactions.
Naily [24]

An atom gains an electron from another atom. Hence, option B is the correct answer.

<h3>What is an atom?</h3>

An atom is a particle of matter that uniquely defines a chemical element. An atom consists of a central nucleus that is usually surrounded by one or more electrons.

When an atom shares electrons with another atom then it results in the formation of a covalent bond.

Whereas when an atom transfer electrons from one atom to another then it results in the formation of an ionic bond.

When the nucleus of an atom splits then it represents a nuclear fission reaction and energy is released during this process.

Hence, option B is the correct answer.

Learn more about the atom here:

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5 0
1 year ago
Use a sheet of paper to answer the following question. Take a picture of your answers and attach to this assignment. Draw the st
pentagon [3]

Answer:

Explanation:

Structure of the 2,2,4,4-tetramethyl-3-pentanone is give in the attachment

In 2,2,4,4-tetramethyl-3-pentanone, no alpha hydrogen is present, therefore, enol form is not possible and hence, exist only in keto form.

Explanation for existence of cyclohexa-2,4-diene-1-one only in enol form:

keto form of cyclohexa-2,4-diene-1-one not aromatic and hence less stable.

Whereas enol form it is aromatic which makes it highly stable. that's why cyclohexa-2,4-diene-1-one exists only in enol form.

8 0
3 years ago
The ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. in t
Debora [2.8K]

The complete balanced chemical equation is: 
4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (g) 

In statement form: 4mol NH3 reacts with 5 mol O2 to produce 6 mol H2O 

First let us find for the limiting reactant: 
>molar mass NH3 = 17 g/mol 
moles NH3 = 54/17 = 3.18 mol NH3 
This will react with 3.18*5/4 = 3.97 mol O2 

>molar mass O2 = 32g/mol 
moles O2 = 54/32 = 1.69 mol O2 
We have insufficient O2 therefore this is the limiting reactant 

From the balanced equation: 
For every 5.0 mol O2, we get 6.0 mol H2O, therefore

moles H2O formed =  1.69 mol O2  * 6/5 = 2.025 mol
Molar mass H2O = 18g/mol 
<span>mass H2O formed = 2.025*18 = 36.45 grams H2O produced</span>

8 0
3 years ago
Read 2 more answers
The standard enthalpy of formation of BrCl(g) is 14.7 kJmol-1 . The standard enthalpies for the atomization of Br2(l) and Cl2(g)
natita [175]

Explanation:

Equation of the reaction:

Br2(l) + Cl2(g) --> 2BrCl(g)

The enthalpy change for this reaction will be equal to twice the standard enthalpy change of formation for bromine monochloride, BrCl.

The standard enthalpy change of formation for a compound,

ΔH°f, is the change in enthalpy when one mole of that compound is formed from its constituent elements in their standard state at a pressure of 1 atm.

This means that the standard enthalpy change of formation will correspond to the change in enthalpy associated with this reaction

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Here, ΔH°rxn = ΔH°f

This means that the enthalpy change for this reaction will be twice the value of ΔH°f = 2 moles BrCl

Using Hess' law,

ΔH°f = total energy of reactant - total energy of product

= (1/2 * (+112) + 1/2 * (+121)) - 14.7

= 101.8 kJ/mol

ΔH°rxn = 101.8 kJ/mol.

8 0
3 years ago
What makes an element more metallic than another?
Valentin [98]
Group names in the periodic table give clues about the metallic properties of the elements.
Metallic elements are found on the left side of the periodic table. A simple conception of metals describes them as a lattice of positive ions immersed in a sea of electrons.
8 0
3 years ago
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