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tino4ka555 [31]

2 years ago

5

HELP ASAP PLEASE PLEASE PLEASE Complete and balance the following reaction. Note that Cr forms +3 in the product. ____ Sn(NO3)2

(aq) + ____ Cr(s) → ____ _________ ( ) + ___ _________( ) b) How do the oxidation states of Sn and Cr change during the reaction? Sn changes from ___ to ____ and Cr changes from ____ to ____ c) Determine the net ionic equation including phases. d) Identify the oxidizing and reducing agents (give formula of compound, ion or element): OA = _____ RA = _____ e) Write the oxidation half rxn.

1 answer:

Rzqust [24]2 years ago

5 0

Answer:

Explanation:

3Sn(NO3)2 (aq) + 2Cr(s) → 2Cr(NO3)3(aq ) + 3Sn(S )

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You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8

Lubov Fominskaja [6]

Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is $pK_a =7.82$

Explanation:

From the question we are told

The volume of base is $V_B = 26.mL = 0.0260L$

The pH of solution is $pH = 7.82$

The concentration of the acid is $C_A = 0.1M$

From the pH we can see that the titration is between a strong base and a weak acid

Let assume that the the volume of acid is $V_A = 18mL= 0.018L$

Generally the concentration of base

$C_B = \frac{C_AV_A}{C_B}$

Substituting value

$C_B = \frac{0.1 * 0.01800}{0.0260}$

$C_B= 0.0692M$

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

$HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}$

Now before the reaction the number of mole of base is

$No \ of \ moles[N_B] = C_B * V_B$

Substituting value

$N_B = 0.01300 * 0.0692$

$= 0.0009 \ moles$

Now before the reaction the number of mole of acid is

$No \ of \ moles = C_B * V_B$

Substituting value

$N_A = 0.01800 *0.1$

$= 0.001800 \ moles$

Now after the reaction the number of moles of base is zero i.e has been used up

this mathematically represented as

$N_B ' = N_B - N_B = 0$

The number of moles of acid is

$N_A ' = N_A - N_B$

$= 0.0009\ moles$

The pH of this reaction can be mathematically represented as

$pH = pK_a + log \frac{[base]}{[acid]}$

Substituting values

$7.82 = pK_a +log \frac{0.0009}{0.0009}$

$pK_a =7.82$

8 0

2 years ago

victus00 [196]

Answer:

This isotope has 59 electrons giving it a charge of -2.

Explanation:

To find this we have to understand isotope relates to the mass of the nucleus. This isotope has 59 electrons to counter the protons and give it a negative charge.

6 0

2 years ago

When excess dilute hydrochloric acid was added to sodium sulphite 960 of sulphuric (iv) oxide was produced. calculate the mass o

irakobra [83]

The mass of sodium sulfite that was used will be 1,890 grams.

<h3>Stoichiometric problems</h3>

First, the equation of the reaction:

$NaSO_3 + 2HCl --- > NaCl_2 + H_2O + SO_2$

The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.

Mole of 960 grams SO2 = 960/64 = 15 moles

Equivalent mole of sodium sulfite that reacted = 15 moles

Mass of 15 moles sodium sulfite = 15 x 126 = 1,890 grams

More on stoichiometric problems can be found here: brainly.com/question/14465605

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1 year ago

Which metal was more reactive in water? How do you know?

Rom4ik [11]

Answer:

alkali metals

Explanation:

they all react vigorously or even explosively with cold water, resulting in the displacement of hydrogen.

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2 years ago

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You can supply activation energy to begin a reaction by _____.

ehidna [41]

If I remember correctly, you would have to heat the reaction beaker over a burner..

I apologize if I'm wrong

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2 years ago

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