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Brut [27]
3 years ago
10

SOLVE A 4.80-gram piece of magnesium displaces 2.76 mL of water when it is placed in a graduated cylinder. What is the density o

f magnesium?
Chemistry
1 answer:
Stels [109]3 years ago
4 0

Answer:

<em>Density = 1.74 gm/mL</em>

Explanation:

Given that:

Mass of piece of Magnesium = 4.80 grams

The volume displaced by this piece = 2.76mL

Let us learn about a property:

Volume of water displaced by a substance when immersed in the water is equal to the Volume of the substance itself.

So, volume of the piece of Magnesium = 2.76 mL

To find:

Density of magnesium = ?

Solution:

Let us have a look at the formula for Density of a Substance:

Density of a substance is given as the ratio of mass of substance and the volume of that mass of substance.

i.e.

Density = \dfrac{Mass}{Volume}

Putting the given values:

Density = \dfrac{4.80}{2.76}\\\Rightarrow \bold{Density = 1.74\ gm/mL}

So, the answer is:

Density of Magnesium = <em>1.74 gm/mL</em>

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16. The concentration of a solution of potassium hydroxide is determined by titration with nitric
____ [38]

Answer:

M_{base}=0.709M

Explanation:

Hello,

In this case, since the reaction between potassium hydroxide and nitric acid is:

KOH+HNO_3\rightarrow KNO_3+H_2O

We can see a 1:1 mole ratio between the acid and base, therefore, for the titration analysis, we find the following equality at the equivalence point:

n_{acid}=n_{base}

That in terms of molarities and volumes is:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, solving the molarity of the base (KOH), we obtain:

M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} =\frac{0.498M*42.7mL}{30.0mL}\\ \\M_{base}=0.709M

Regards.

3 0
3 years ago
You have a pound of feathers and a pound of lead:
mafiozo [28]
Feathers have more density and less have more mass, feather is super light and a POUND of led isnt
6 0
3 years ago
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A compound is a type of matter true or false
Dominik [7]
Yes, a compound is a type of matter.
7 0
3 years ago
Read 2 more answers
Calculate delta Gº for the following system:
Llana [10]

Answer:

ΔG = - 442.5  KJ/mol    

Explanation:

Data Given

delta H = -472 kJ/mol

delta S = -108 J/mol K

So,

delta S = -0.108 J/mol K

delta Gº = ?

Solution:

The answer will be calculated by the following equation for the Gibbs free energy

                    G = H - TS

Where

G = Gibbs free energy

H = enthalpy of a system (heat

T = temperature

S = entropy

So the change in the Gibbs free energy at constant temperature can be written as

                ΔG = ΔH - TΔS . . . . . . (1)

Where

ΔG = Change in Gibb’s free energy

ΔH = Change in enthalpy of a system

ΔS = Change in entropy

if system have standard temperature then

T = 273.15 K

Now,

put values in equation 1

                  ΔG = (-472 kJ/mol) - 273.15 K (-0.108 KJ/mol K)

                 ΔG = (-472 kJ/mol) - (-29.5 KJ/mol)

                 ΔG = -472 kJ/mol + 29.5 KJ/mol

                 ΔG = - 442.5  KJ/mol          

7 0
2 years ago
How many grams of CaF2 would be needed to produce 1.23 moles of F2?
NemiM [27]

We see from the chemical formula itself that there is 1 mole of F2 for every 1 mole of CaF2, hence the number of moles of CaF2 is also:

moles CaF2 = 1.23 moles

 

The molar mass of CaF2 is 78.07 g/mol, so the mass is:

mass CaF2 = 78.07 g / mol * 1.23 mol

<span>mass CaF2 = 96.03 grams</span>

5 0
2 years ago
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