<span>the molar mass of a compound is the sum of the products of the atomic masses by the number of atoms of the element.
molar mass of Na</span>₂SO₄<span> is - 142 g/mol.
1 mol of </span>Na₂SO₄<span> has a mass of 142 g.
In 1 mol of </span>Na₂SO₄<span> the mass of Na is 23 g/mol x 2 = 46 g.
Mass of Na in 1 mol of </span>Na₂SO₄ is - 46 g
mass of Na in 0.820 mol of Na₂SO₄ - 46 g /1 mol x 0.820 mol = 37.72 g.
mass of Na is 37.72 g
Answer:
Detail is given below.
Explanation:
Similarities:
All are the forms of matter.
Solid, liquid and gases are made up of ions, atoms and molecules.
They have shape and volume.
Molecules in Liquid and solid are closer to each others.
Liquid and gases can flow very easily.
Liquid and solid both can not compressed very easily.
Differences:
Molecule of gases randomly move everywhere and occupy all available space but liquid and solid's molecules are not move as much easier as molecules of gases can.
The density of gases are very low as compared to the liquid and solid.
Gas molecules are at long distance from each other while in liquid and solid they are closer to each other.
The very weak inter molecular forces are present between gas molecules as compared to the liquid and solids.
Solids have definite volume and shape but liquid and gases acquire the shape of container.
In solids molecules are tightly pack and very close to each other while in liquid molecules are not tightly pack like in case of solid.
The densities of solids are also very high as compared to the liquid and gas.
There are very strong inter molecular forces are present between solid molecules.
Answer:
Therefore, the rate of change in the amount of salt is 
Explanation:
Given:
Initial volume of water 
lit
Flowing rate = 5 
The rate of change in the amount of salt is given by,
( Rate of salt enters tank - rate of sat leaves tank )
Since tank is initially filled with water so we write that,
Let amount of salt in the solution is 
,
Therefore, the rate of change in the amount of salt is
Answer is: <span>the molarity of the diluted solution 0,454 M.
</span>V₁(NaOH) = 100 mL ÷ 1000 mL/L = 0,1 L.
c₁(NaOH) = 0,75 M = 0,75 mol/L.
n₁(NaOH) = c₁(NaOH) · V₁(NaOH).
n₁(NaOH) = 0,75 mol/L · 0,1 L.
n₁(NaOH) = 0,075 mol
n₂(NaOH) = n₁(NaOH) = 0,075 mol.
V₂(NaOH) = 165 mL ÷ 1000 mL/L = 0,165 L.
c₂(NaOH) = n₂(NaOH) ÷ V₂(NaOH).
c₂(NaOH) = 0,075 mol ÷ 0,165 L.
c₂(NaOH) = 0,454 mol/L.
A. Carbon monoxide
b. Phosphorous trichloride
c.
d.nitrogen
e. Water- Hydrogen - Oxygen
f.
