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3 years ago

Given: △ABC≅△DEF, △KLM≅△DEF

Mathematics

1 answer:

lesantik [10]3 years ago

6 0

I reccomend that you add an image or better explain what you want us to do.

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What is the range of the function y = x 2?

garik1379 [7]

Answer:

The range of the function y = x2 is all real numbers, y, such that y ≥ 0. In the case of the function y = x2, the domain consists of all real numbers, because there is no number that, when plugged in for x into x2, would create an undefined expression.

Step-by-step explanation:

7 0

3 years ago

Simplify √ 320 A. 8√ 5 B. 4√ 2 C. 14√ 2 D. 5√ 7

antoniya [11.8K]

According to my calculations,

A. is the correct answer.

8√5

6 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

Expanding/Factoring

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

<u>Step 2: Differentiate</u>

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago

Which is the sum of 3/10 and 1/3

Ilya [14]

Step-by-step explanation:

$\: \: \: \: \: \frac{3}{10} + \frac{1}{3} \\ \\ = \frac{3 \times 3}{10 \times 3} + \frac{1 \times 10}{3 \times 10} \\ \\ = \frac{9}{30} + \frac{10}{30} \\ \\ = \frac{19}{30} \\ \\ so \: as \: you \: see \: here \: we \: should \: put \: same \: denominator \\ \: for \: both \: fractions. \: hope \: this \: helps.. \\ good \: luck$