J/-2 + 7 = -12 multiply both sides with 2
-j + 14 = -24 move -14 to the other side and change sign
-j= -24 - 14
-j = -38 and if you divide -38 with -1 you get + 38
j=38
$12.6 -- 25% of 12.6 is exactly $3.15
I did this by taking 3.15 / 0.25
Answer:
25.5 and 1.5
Step-by-step explanation:
AC = 12 cm
BC = 13.5 cm
12 + 13.5 = 25.5 cm
13.5 - 12 = 1.5 cm
Answer:
Statement, Reason
Given segment RV = segment TU, Given
m∠R = m∠T, Given
Segment RS ≅ segment ST, Base angles theorem
ΔRSV ≅ ΔTSU, SAS rule of congruency
Segment SV ≅ segment SU, CPCTC
VU ≅ UV, Reflexive property
RU = RV + VU, TV = TU + UV, Addition of segments
RV + VU ≅ TU + UV, Addition property of equality
RU ≅ TV, Transitive property of addition
ΔRSU ≅ ΔTSV, SSS rule of congruency
Step-by-step explanation:
Where:
SAS- Side Angle Side
CPCTC -Congruent Parts of Congruent Triangles are Congruent
SSS -Side Side Side
You just need to solve for when
:





where
is any integer. We only care about when
, which happens for
.
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
