Question

How far will a stone travel over level ground if it is thrown upward at an angle of 30.0° with respect to the horizontal and with a speed of 11.0 m/s? What is the maximum range that could be achieved with the same initial speed?

Answer 1

Explanation:

It is given that, a stone travel over level ground if it is thrown upward at an angle of 30.0° with respect to the horizontal.

Speed with which it is thrown, v = 11 m/s

We need to find the maximum height above the ground level. The maximum height attained by the stone is given by :

$h=\dfrac{v^2sin^2\theta}{2g}$

$h=\dfrac{(11\ m/s)^2sin^2(30)}{2\times 9.8\ m/s^2}$

h = 1.54 m

So, the stone will travel a distance of 1.54 meters.

Range of a projectile is given by :

$R=\dfrac{v^2sin\ 2\theta}{g}$

$R=\dfrac{(11\ m/s)^2sin(60)}{9.8\ m/s^2}$

R = 10.69 m

So, the maximum range achieved with the same initial speed is 10.69 meters. Hence, this is the required solution.