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Blababa [14]
3 years ago
11

You venture out on a cold winter morning to warm up your vehicle. You have layers of cotton/polyester blend clothes on and from

walking on carpeting you have accumulated a net negative charge. Your car is considered a neutral conductor. As you place your hand near the door handle (without touching it) what happens to the charges of your car?
A. There is a localization of positive charge near the door handle.
B. Nothing, since your hand is not touching the car it cannot transfer any charge.
C. Nothing, the charges are too cold to deliver any response.
D. There is a localization of negative charge near the door handle.
Physics
1 answer:
maxonik [38]3 years ago
3 0

Answer:

A. There is a localization of positive charge near the door handle.

Explanation:

  • When on a cold morning a person wearing cotton/ polyester cloth walking on the carpet moves toward his car then due to friction between the feet and the carpet there are transfer of electrons from the carpet to our feet, and since our body is a good conductor of electricity the charges spread throughout on the surface of or body.
  • When the person brings his hands close to the neutral conducting door of the car it gets induced with equal intensity of opposite charge to our hands thus having a concentration of positive charges near to the hand on the car's door is developed as a result of polarization within the conductor.
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P=W/T
=51*6/9

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During both the vernal equinox and _____________, there is an equal amount of night and day.
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a bird flies 25.0 m in the direction 55° east of south to its nest. the bird then flies 75.0 m in the direction 55° west of nort
son4ous [18]

The northward components of the resultant displacement is 40.96 m and the westward components of the resultant displacement of the bird from its nest is 28.68 m.

<h3>Displacement of the bird</h3>

The displacement of the bird is the change in the position of the bird.

<h3>Vertical component of the bird's displacement </h3>

Vy₁ = -25 m  x   sin(55)

Vy₁ = -20.48 m

Vy₂ = 75 m   x    sin(55)

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<h3>Horizontal component of the bird's displacement </h3>

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Vx₁ = -14.34 m

Vx₂ = 75 m   x    cos(55)

Vx₂ = 43.02 m

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Learn more about displacement here: brainly.com/question/2109763

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8 0
1 year ago
One end of a metal rod is in contact with a thermal reservoir at 745. K, and the other end is in contact with a thermal reservoi
Masteriza [31]

Answer:

a)S_1=-9.65}\ J/K

b)S_2=71.18\ J/K

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Explanation:

Given that

T₁ = 745 K

T₂ = 101 K

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The entropy change of reservoir 745 K

S_1=-\dfrac{7190}{745}\ J/K

Negative sign because heat is leaving.

S_1=-9.65}\ J/K

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The entropy change of the rod will be zero.

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The entropy change of the system

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S = 71.18 - 9.65 J/K

S= 61.53 J/K

3 0
3 years ago
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