Answer:
here we can say that acceleration of the satellite is same as the gravitational field due to Earth at that location
Explanation:
As we know that gravitational field is defined as the force experienced by the satellite per unit of mass
so we will have
now in order to find the acceleration of the satellite we know by Newton's II law
so we will have
so here we can say that acceleration of the satellite is same as the gravitational field due to Earth at that location
Answer:
a) 3.0 x 10¹⁰ J
b) 7.75 x 10³ m/s
Explanation:
a)
ΔV = potential difference between cloud and the ground = 1.0 x 10⁹ Volts
Q = Amount of charge transferred = 30 C
ΔU = Change in energy transferred
Change in energy transferred is given as
ΔU = Q ΔV
ΔU = (30) (1.0 x 10⁹)
ΔU = 3.0 x 10¹⁰ J
b)
v₀ = initial speed of the automobile = 0 m/s
v = final speed of the automobile = ?
m = mass of automobile = 1000 kg
Using conservation of energy
ΔU = (0.5) m (v² - v₀²)
3.0 x 10¹⁰ = (0.5) (1000) (v² - 0²)
v = 7.75 x 10³ m/s
Decay Rate
The half-life (t1/2) is the time taken for the activity of a given amount of a radioactive substance to decay to half of its initial value. The mean lifetime (τ, “tau”) is the average lifetime of a radioactive particle before decay. The decay constant (λ, “lambda”) is the inverse of the mean lifetime.
The rate of radioactive decay is an intrinsic property of each radioactive isotope that is independent of the chemical and physical form of the radioactive isotope. ... Activity is usually measured in disintegrations per second (dps) or disintegrations per minute (dpm).
It is called surface tension.
Hope that helped you.