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3 years ago

Questlon 7 of 10

Physics

2 answers:

katovenus [111]3 years ago

6 0

Answer:

Plasma

Explanation:

Aye pecks said so

jek_recluse [69]3 years ago

5 0

Answer:

0B. Liqiud can always conduct electricity

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Two identical masses are connected to two different flywheels that are initially stationary. Flywheel A is larger and has more m

inysia [295]

Answer:

a) True. There is dependence on the radius and moment of inertia, no data is given to calculate the moment of inertia

c) True. Information is missing to perform the calculation

Explanation:

Let's consider solving this exercise before seeing the final statements.

We use Newton's second law Rotational

τ = I α

T r = I α

T gR = I α

Alf = T R / I (1)

T = α I / R

Now let's use Newton's second law in the mass that descends

W- T = m a

a = (m g -T) / m

The two accelerations need related

a = R α

α = a / R

a = (m g - α I / R) / m

R α = g - α I /m R

α (R + I / mR) = g

α = g / R (1 + I / mR²)

We can see that the angular acceleration depends on the radius and the moments of inertia of the steering wheels, the mass is constant

Let's review the claims

a) True. There is dependence on the radius and moment of inertia, no data is given to calculate the moment of inertia

b) False. Missing data for calculation

c) True. Information is missing to perform the calculation

d) False. There is a dependency if the radius and moment of inertia increases angular acceleration decreases

4 0

4 years ago

Find the current passing through a circuit consisting of a battery and one resistor. The resistance has a retance of 2ohms and t

Bingel [31]

The current passing through a circuit consisting of a battery of 12 V and resistor of 2 ohms is 6 Ampere .

Explanation:

Assume the wires are ideal with zero resistance.

The current passing through the circuit will be

I = V/R = 12/2 = 6.000 A.

5 0

3 years ago

A piece of aluminum has a volume of 1.50 10-3 m3. the coefficient of volume expansion for aluminum is β = 69 ✕ 10-6 (°c)-1. the

Alex17521 [72]

Answer:

W = 3.12 J

Explanation:

Given the volume is 1.50*10^-3 m^3 and the coefficient of volume for aluminum is β = 69*10^-6 (°C)^-1. The temperature rises from 22°C to 320°C. The difference in temperature is 320 - 22 = 298°C, so ΔT = 298°C. To reiterate our known values we have:

β = 69*10^-6 (°C)^-1 V = 1.50*10^-3 m^3 ΔT = 298°C

So we can plug into the thermal expansion equation to find ΔV which is how much the volume expanded (I'll use d instead of Δ because of format):

$dV = \beta V_{0} dT\\dV = (69*10^{-6})( C)^{-1} * (1.50*10^{-3})m^{3} * (298)C\\dV = 3.0843*10^-5$

So ΔV = 3.0843*10^-5 m^3

Now we have ΔV, next we have to solve for the work done by thermal expansion. The air pressure is 1.01 * 10^5 Pa

To get work, multiply the air pressure and the volume change.

$W = P * dV = (1.01 * 10^5)Pa * (3.0843*10^{-5})m^3\\W = 3.115143J$

W = 3.12 J

Hope this helps!

4 0

3 years ago

Sugar molecules can be oxidized in the cell of animals . This oxidation releases energy for the animal to use. From what soured

qaws [65]

Answer: through digested food

Explanation: cells get their sugar molecules from the food that is taken in by an organism. The food taken in is digested by the stomach into base materials like sugar, fatty acids and amino acids. These base materials are circulated through the blood till they get to the cells where they are needed.

4 0

3 years ago

Read 2 more answers

You need to fill a basketball with air to play with it. You know that your pump expels air at a velocity of 6 cm/s. You know tha

Scrat [10]

Answer:

The diameter of the needle is <u>4.675 cm</u>.

Explanation:

Given:

Volume flow rate is, $\dot V=103\ cm^3$

Velocity of air expelled by pump is, $v=6\ cm/s$

Let the area of the needle be 'A' cm² and the diameter be 'd' cm.

We know that, volume flow rate of the air expelled by pump is given as the product of the needle's area and velocity of air flowing through that area.

Therefore, volume flow rate is given as:

$\dot V=A\times v\\\\103=A\times 6\\\\6A=103\\\\A=\frac{103}{6}\ cm^2$

Now, considering the needle to be circular, area of the needle can be written as:

$A=\frac{\pi}{4}\times d^2\\\\\frac{103}{6}=\frac{\pi}{4}\times d^2\\\\d^2=\frac{103\times 4}{6\pi}\\\\d=\sqrt{\frac{103\times 4}{6\pi}}\\\\d=4.675\ cm$

Therefore, the diameter of the needle is 4.675 cm.

8 0

3 years ago