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2 years ago

which characteristic of a vibrating body determines the (a) loudness (b) pitch of the sound produced by it?

2 answers:

7 0

The loudness depends on the amplitude of the vibration. It will be louder when the amplitude is high. Suppose when we pluck a string of the sitar it starts vibrating with low amplitude and if we apply more energy by plucking more strongly, the string will vibrate with the greater amplitude and produce a loud sound.

Hope this helps,

Davinia.

riadik2000 [5.3K]2 years ago

4 0

-- The loudness of the vibration is determined by its <em>amplitude</em>.

-- The pitch of the vibration is determined by its <em>frequency</em>.

-- The amplitude and frequency of the vibration are determined by the material characteristics of the body that's vibrating, and by how much energy is used to start the vibrations.

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The kinetic theory describes the __1__ of particles in matter and the forces of attraction between them. The theory assumes that

frutty [35]

Answer:

1. Motion

2. Empty space

3. Far apart

4. Independently

5. Random or rapid

6. Collision

7. Kinetic energy

8. Atmospheric

9. 273 Kelvin or 0° Celsius

10. 1 atm, 101.3 kPa or 760 mmHg

Explanation:

In science, matter can be defined as anything that has mass and occupies space. Any physical object that is found on earth is typically composed of matter. Matter are known to be made up of atoms and as a result has the property of existing in states.

Generally, matter exists in three (3) distinct or classical phases and these are;

I. Gas.

II. Solid.

III. Liquid.

Filling the missing words or texts in the question, we have;

The kinetic theory describes the motion of particles in matter and the forces of attraction between them. The theory assumes that the volume occupied by a gas is mostly empty space, that the particles of gas are relatively far apart, move independently of each other, and are in constant random or rapid motion. The collision between particles are perfectly elastic so that the total kinetic energy remains constant. Gas pressure results from the simultaneous collisions of billions of particles with an object. Barometers are used to measure atmospheric pressure. Standard conditions are defined as a temperature of 273 Kelvin or 0° Celsius and a pressure of 1 atm, 101.3 kPa or 760 mmHg.

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2 years ago

The _____ rip and grind food into small chunks.

masya89 [10]

It would have helped to answer this question, if there were some options to choose from. I am answering the question based on what i understood. I hope that it helps you. The teeth rip and grind food into small chunks. This is also the main function of the teeth and it does help in the digestion of the food we take.

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3 years ago

The points plotted on a graph represent the actual data recorded by an experiment.

aleksandr82 [10.1K]

True. Depending how accurate the graph is plotted

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3 years ago

Read 2 more answers

Which of these are a covalent compound?

nikdorinn [45]

C is a non-metal and so is O. So the answer is CO

8 0

2 years ago

A parallel-plate capacitor is charged by connecting it to a battery. If the battery is disconnected and then the separation betw

TEA [102]

Answer:

The charge stored in the capacitor will stay the same. However, the electric potential across the two plates will increase. (Assuming that the permittivity of the space between the two plates stays the same.)

Explanation:

The two plates of this capacitor are no longer connected to each other. As a result, there's no way for the charge on one plate to move to the other. $Q$ , the amount of charge stored in this capacitor, will stay the same.

The formula $\displaystyle Q = C\, V$ relates the electric potential across a capacitor to:

$Q$ , the charge stored in the capacitor, and
$C$ , the capacitance of this capacitor.

While $Q$ stays the same, moving the two plates apart could affect the potential $V$ by changing the capacitance $C$ of this capacitor. The formula for the capacitance of a parallel-plate capacitor is:

$\displaystyle C = \frac{\epsilon\, A}{d}$ ,

where

$\epsilon$ is the permittivity of the material between the two plates.
$A$ is the area of each of the two plates.
$d$ is the distance between the two plates.

Assume that the two plates are separated with vacuum. Moving the two plates apart will not affect the value of $\epsilon$ . Neither will that change the area of the two plates.

However, as $d$ (the distance between the two plates) increases, the value of $\displaystyle C = \frac{\epsilon\, A}{d}$ will become smaller. In other words, moving the two plates of a parallel-plate capacitor apart would reduce its capacitance.

On the other hand, the formula $\displaystyle Q = C\, V$ can be rewritten as:

$V = \displaystyle \frac{Q}{C}$ .

The value of $Q$ (charge stored in this capacitor) stays the same. As the value of $C$ becomes smaller, the value of the fraction will become larger. Hence, the electric potential across this capacitor will become larger as the two plates are moved away from one another.

3 0

2 years ago