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2 years ago

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A spring of spring constant 25 N/m is hung vertically and a 0.300 kg mass is attached to one end, causing a displacement of the

end of the spring of _____ m.

1 answer:

Mamont248 [21]2 years ago

3 0

Answer:k=1175

Explanation:thank you for asking

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The light coming out of a concave lens:

torisob [31]

The light coming out of a concave lens will never meet.

So, the answer is A. will never meet.

Happy Studying! ^^

4 0

3 years ago

Read 2 more answers

A 3 kg mass object is pushed 0.6 m into a spring with spring constant 210 N/m on a frictionless horizontal surface. Upon release

Svetradugi [14.3K]

Answer with Explanation:

We are given that

Mass of spring,m=3 kg

Distance moved by object,d=0.6 m

Spring constant,k=210N/m

Height,h=1.5 m

a.Work done to compress the spring initially= $\frac{1}{2}kx^2=\frac{1}{2}(210)(0.6)^2=37.8J$

b.

By conservation law of energy

Initial energy of spring=Kinetic energy of object

$37.8=\frac{1}{2}(3)v^2$

$v^2=\frac{37.8\times 2}{3}$

$v=\sqrt{\frac{37.8\times 2}{3}}$

v=5.02 m/s

c.Work done by friction on the incline, $w_{friction}=P.E-spring \;energy$

$W_{friction}=3\times 9.8\times 1.5-37.8=6.3 J$

8 0

3 years ago

Which of the following activities belongs on the top of the physical activity for pyramid

jasenka [17]

Playing Vedio Games. :)

7 0

3 years ago

Exercise that strengthens your heart, increases your lung capacity, and helps you to burn fate and lose weight is..

olga2289 [7]

Answer : Cardio training

Explanation : Cardio exercise helps improve lung function , strengthens your heart and improve your endurance and increases lung capacity. The peoples do cardio is burn calories and lose the weight.

Cardio helps decrease your heart rate and blood pressure and improve your breathing.

8 0

3 years ago

A heavy ball with a weight of 150 N is hung from the ceiling of a lecture hall on a 4.1-m-long rope. The ball is pulled to one s

AlladinOne [14]

Answer:

The tension in the rope is 262.88 N

Explanation:

Given:

Weight $W = 150$ N

Length of rope $r = 4.1$ m

Initial speed of ball $v = 5.5 \frac{m}{s}$

For finding the tension in the rope,

First find the mass of rod,

$mg = 150$ ( $g = 9.8 \frac{m}{s^{2} }$ )

$m = \frac{150}{9.8}$

$m = 15.3$ kg

Tension in the rope is,

$T = mg + \frac{mv^{2} }{r}$

$T = 150 + \frac{15.3 \times (5.5)^{2} }{4.1}$

$T = 262.88$ N

Therefore, the tension in the rope is 262.88 N

7 0

3 years ago