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Marianna [84]
3 years ago
10

A spring of spring constant 25 N/m is hung vertically and a 0.300 kg mass is attached to one end, causing a displacement of the

end of the spring of _____ m.
Physics
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:k=1175

Explanation:thank  you for asking

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To be skeptical when you hear new information means that you should _____.
adelina 88 [10]

Answer:

C.

Explanation:

I TOOK THE TEST

3 0
3 years ago
Read 2 more answers
Describe at least three measures that ensure safety and prevent injury during a workout.
KonstantinChe [14]
Water - helps with dehydration.
instruction - help you understand how you need to do the workout.
trainers - wether it's an online trainer or a gym trainer they always say how to be safe while working out.
5 0
3 years ago
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Josie is running her first cross country meet. The race is a distance of 5 km and she has set a goal to finish the race in 21 mi
frutty [35]

Answer:

3.97 m/s

Explanation:

Speed is defined as the distance covered per unit time. Therefore, s=d÷t=d/t

Where d is distance and t is time

Given distance of 5 km and time of 21 minutes the speed would be given by dividing 5 km by 21 min. However, speed is expressed as km/h or m/s or miles per hour etc. So we nees to get our speed in one of these standard units.

Going for m/s

Conversion

1 km has 1000m hence

5 km=5*1000=5000m

1 min has 60 seconds hence

21 min=21*60=1260 s

Speed=5000m÷1260s=3.9682539682538 m/s

Rounded off, s=3.97 m/s

8 0
3 years ago
1. What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30 m?
aivan3 [116]

Answer:

1. v = 30 m/s

2. v = 5 m/s

3. f = 40 Hz

4. f = 400 Hz

5. f = 300 Hz

6. λ = 0.772 m

7. λ = 0.386 m

8. λ = 0.625 m

9. v = 100 m/s

10. v = 50 m/s

Explanation:

The relationship between frequency, wavelength, and speed of a wave is given by the following formula:

v = f\lambda

where,

v = speed of wave

f = frequency of wave

λ = wavelength

1.

f = 100 Hz

λ = 0.3 m

Therefore,

v = (100 Hz)(0.3 m)

<u>v = 30 m/s</u>

<u></u>

2.

f = 50 Hz

λ = 0.1 m

v = (50 Hz)(0.1 m)

<u>v = 5 m/s</u>

<u></u>

3.

v = 20 m/s

λ = 0.5 m

f = \frac{v}{\lambda} = \frac{20\ m/s}{0.5\ m}

<u>f = 40 Hz</u>

<u></u>

4.

v = 80 m/s

λ = 0.2 m

f = \frac{v}{\lambda}=\frac{80\ m/s}{0.2\ m}

<u>f = 400 Hz</u>

<u></u>

5.

v = 120 m/s

λ = 0.4 m

f = \frac{v}{\lambda}=\frac{120\ m/s}{0.4\ m}

<u>f = 300 Hz</u>

<u></u>

6.

v = 340 m/s

f = 440 Hz

\lambda = \frac{v}{f}=\frac{340\ m/s}{440\ Hz}\\

<u>λ = 0.772 m</u>

<u></u>

7.

v = 340 m/s

f = 880 Hz

\lambda = \frac{v}{f}=\frac{340\ m/s}{880\ Hz}\\

<u>λ = 0.386 m</u>

<u></u>

<u></u>

8.

v = 250 m/s

f = 400 Hz

\lambda = \frac{v}{f}=\frac{250\ m/s}{400\ Hz}\\

<u>λ = 0.625 m</u>

<u></u>

9.

f = 50 Hz

λ = 2 m

v = (50 Hz)(2 m)

<u>v = 100 m/s</u>

<u></u>

10.

f = 100 Hz

λ = 0.5 m

v = (100 Hz)(0.5 m)

<u>v = 50 m/s</u>

6 0
3 years ago
To what potential should you charge a 2.0 μF capacitor to store 1.0 J of energy?
Bess [88]
E = (1/2)CV²
1 = (1/2)*(2*10⁻⁶)V²
10⁶ = V²
1000 = V

You should charge it to 1000 volts to store 1.0 J of energy.
6 0
3 years ago
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