Answer:
the mass of water is 0.3 Kg
Explanation:
since the container is well-insulated, the heat released by the copper is absorbed by the water , therefore:
Q water + Q copper = Q surroundings =0 (insulated)
Q water = - Q copper
since Q = m * c * ( T eq - Ti ) , where m = mass, c = specific heat, T eq = equilibrium temperature and Ti = initial temperature
and denoting w as water and co as copper :
m w * c w * (T eq - Tiw) = - m co * c co * (T eq - Ti co) = m co * c co * (T co - Ti eq)
m w = m co * c co * (T co - Ti eq) / [ c w * (T eq - Tiw) ]
We take the specific heat of water as c= 1 cal/g °C = 4.186 J/g °C . Also the specific heat of copper can be found in tables → at 25°C c co = 0.385 J/g°C
if we assume that both specific heats do not change during the process (or the change is insignificant)
m w = m co * c co * (T eq - Ti co) / [ c w * (T eq - Tiw) ]
m w= 1.80 kg * 0.385 J/g°C ( 150°C - 70°C) /( 4.186 J/g°C ( 70°C- 27°C))
m w= 0.3 kg
Answer:
Explanation:
We are given that
|v|=11
|w|=23
|v-w|=30
We have to find the value of |v+w|
|a-b|^2=(a+b)\cdot (a+b)=a^2+b^2-2|a||b|cos\theta
Using the formula
Using the formula
Answer:
55.28 m
Explanation:
Mass of the rocket = 950 g = 950 / 1000 = 0.95 kg
force of gravity = 0.95 Kg × 9.81 m/s² = 9.3195 N
force due to acceleration = 18.3 N - 9.3195 N = 8.9805 N
F = ma
acceleration of the rocket = F / m = 8.9805 N / 0.95 Kg = 9.45 m/s²
using the equation of motion
d = ut + 1/2 at² u = 0 m/s
d = 1/2 at²
t = √(2d / a) = √ ( 2 × 40 m / 9.45 m/s²) = 2.91 s
the horizontal distance between the target and the rocket = vt = 19 m/s × 2.91 s = 55.28 m
Answer:
Angular momentum
Explanation:
Stars are formed as a result of a collapse of a low-temperature cloud of gas and dust. During the colapse conservation of angular momentum causes any small net rotation of the cloud to increase thus forcing the material into rotating
