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lutik1710 [3]
2 years ago
9

Rocket-powered sleds are been used to test the responses of humans to acceleration. Starting from rest, one sled can reach a spe

ed of 495 m/s in 1.78 s and can be brought to a stop again in 2.16 s.
Find the acceleration of the sled while accelerating.
Please be very thorough in your answer, I have a very hard time understanding if you don't.
Also, find the acceleration of the sled when braking.
Physics
1 answer:
Greeley [361]2 years ago
3 0

Answer:cho  v₀ =0s  

α=Δv/Δt

Explanation:

\frac{0-495}{2,16-1,78}

=-1302,631579

chuyển động chậm dầnđều

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A Young'sdouble-slit interference experiment is performed with monochromatic light. The separation between the slits is 0.44 mm.
Artyom0805 [142]

Answer:

Explanation:

The double slit interference phonemene is described for the case of constructive interference

          d sin θ= m λ                   (1)

let's use trigonometry to find the sinus

        tan θ = y / L

in general in interference phenomena the angles are small

       tan θ = sin θ / cos θ = sin θ

 

The double slit interference phonemene is described for the case of constructive interference

          d sin θ = m lam                    (1)

let's use trigonometry to find the sinus

        tan θ = y / L

in general in interference phenomena the angles are small

       tan θ = sin θ / cos θ = sin θ

we substitute

      sin θ = y / L

we substitute in equation 1

         d y / L = m λ

         λ = dy / L m

let's reduce the magnitudes to the SI system

  d = 0.44 mm = 0.44 10⁻³ m

  y = 5.5 mm = 5.5 10⁻³ m

  L = 4.2m

  m = 1

let's calculate

        λ = 0.44  10⁻³ 5.5 10⁻³ / (4.2 1)

         

        λ = 5.76190 10-7 m

let's reduce to num

  lam = 5.56190 10-7 m (109 nm / 1m)

  lam = 556,190 nmtea

we substitute

      without tea = y / L

we substitute in equation 1

         d y / L = m lam

         lam = dy / L m

let's reduce the magnitudes to the SI system

  d = 0.44 me = 0.44 10-3 m

  y = 5.5 mm = 5.5 10-3

  L = 4.2m

  m = 1

let's calculate

        lam = 0.44 10⁻³  5.5 10⁻³ / (4.2 1)

         

        lam = 5.76190 10⁻⁷ m

let's reduce to num

  lam = 5.56190 10⁻⁷ m (109 nm / 1m)

  lam = 556,190 nm

6 0
3 years ago
A process generates 250 watts of useful energy and 600 watts of waste energy. WhT is the efficiency of the process?
Cloud [144]

The efficiency of the process is 42%

From the question given above, the following data were obtained:

Useful energy = 250 watt

Wasteful energy = 600 watt

<h3>Efficiency =? </h3>

The efficiency of the process can be obtained as illustrated below:

efficiency \:  =  \frac{useful \: energy}{wasteful \: energy}  \times 100 \\  \\ efficiency \:  =  \frac{250}{600}  \times 100 \\

<h3>Efficiency = 42%</h3>

Therefore, the efficiency of the process is 42%

Learn more: brainly.com/question/2300041

3 0
2 years ago
The A string of a violin is a little too tightly stretched. Beats at 4.00 per second are heard when the string is sounded togeth
Basile [38]

Answer:

T=2.5*10^{-3}s

Explanation:

From the question we are told that:

Beat frequency F_b=4

Frequency F=400Hz

Generally the equation for Frequency of the violin is mathematically given by

 f_v=F_b+F

 f_v=4+400Hz

 f_v=404Hz

Therefore the period of the violin string oscillations is

 T=\frac{1}{f_v}

 T=\frac{1}{404}

 T=2.5*10^{-3}s

3 0
2 years ago
What kind of wave (transverse of longitudinal) is each of the following and why?
Elina [12.6K]

Answer:

1.) Longitudinal waves

2.) Transverse waves

3.) Longitudinal waves

Explanation:

The sound of one whale calling another whale underwater.  is a longitudinal wave since the medium, in this case the body of water, is vibrating parallel to the direction of propagation of the wave.

A pulse sent down a stretched rope by snapping one end of it. ( transverse wave) because its oscillations are perpendicular to the direction of the wave or path of propagation

The vibrations in a guitar string

Longitudinal wave. Because its oscillations are parallel to the direction of the wave or path of propagation

5 0
3 years ago
a rocket initially at rest on the ground lifts off vertically with a constant acceleration of 2.0 x 10^1 meters per second^2. Ho
xenn [34]

Here's the formula for the distance covered by an accelerating body in some amount of time ' T '. This formula is incredibly simple but incredibly useful. It pops up so often in Physics that you really should memorize it:

D = 1/2 a T²

Distance = (1/2)·(acceleration)·(time²)

This question gives us the acceleration and the distance, and we want to find the time.

(9,000 m) = (1/2) (20 m/s²) (time²)

(9,000 m) = (10 m/s²) (time²)

Divide each side by 10 m/s²:

(9,000 m) / (10 m/s²) = (time²)

900 s² = time²

Square root each side:

<em>T = 30 seconds</em>

7 0
2 years ago
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