Answer:
Answer is D.window units / small residential units
Refer below.
Explanation:
Rotary compressors are used primarily in window units / small residential units
Answer:
![v_{o}=141.51m/s](https://tex.z-dn.net/?f=v_%7Bo%7D%3D141.51m%2Fs)
Explanation:
From the exercise we know the final x distance, the angle which the projectile is being released and acceleration of gravity
![x=1420m\\g=-9.8m/s^{2}](https://tex.z-dn.net/?f=x%3D1420m%5C%5Cg%3D-9.8m%2Fs%5E%7B2%7D)
From the equation of x-position we know that
![x=v_{ox}t=v_{o}cos(35)t](https://tex.z-dn.net/?f=x%3Dv_%7Box%7Dt%3Dv_%7Bo%7Dcos%2835%29t)
Solving for ![v_{o}](https://tex.z-dn.net/?f=v_%7Bo%7D)
(1)
Now, if we analyze the equation of y-position we got
![y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}](https://tex.z-dn.net/?f=y%3Dy_%7Bo%7D%2Bv_%7Boy%7Dt%2B%5Cfrac%7B1%7D%7B2%7Dgt%5E%7B2%7D)
At the end of the motion y=0
![0=v_{o}sin(35)t+\frac{1}{2}gt^{2}](https://tex.z-dn.net/?f=0%3Dv_%7Bo%7Dsin%2835%29t%2B%5Cfrac%7B1%7D%7B2%7Dgt%5E%7B2%7D)
Knowing the equation for
in (1)
![0=\frac{1420}{tcos(35)}tsin(35)-\frac{1}{2}(9.8)t^{2}](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B1420%7D%7Btcos%2835%29%7Dtsin%2835%29-%5Cfrac%7B1%7D%7B2%7D%289.8%29t%5E%7B2%7D)
![\frac{1}{2}(9.8)t^{2}=1420tan(35)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%289.8%29t%5E%7B2%7D%3D1420tan%2835%29)
Solving for t
Now, we can solve (1)
![v_{o}=\frac{1420m}{(14.25s)cos(35)}=141.51m/s](https://tex.z-dn.net/?f=v_%7Bo%7D%3D%5Cfrac%7B1420m%7D%7B%2814.25s%29cos%2835%29%7D%3D141.51m%2Fs)
Answer:
answer is 3.05v
Explanation:
hope it is helpful and briliant
Answer:
![v = 10.75\,\frac{m}{s}](https://tex.z-dn.net/?f=v%20%3D%2010.75%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
Explanation:
The system ball-pin is modelled by the Principle of Moment Conservation:
![(9\,kg)\cdot (15\,\frac{m}{s} ) + (0.85\,kg)\cdot (0\frac{m}{s} ) = (9\,kg)\cdot v + (0.85\,kg)\cdot (45\,\frac{m}{s} )](https://tex.z-dn.net/?f=%289%5C%2Ckg%29%5Ccdot%20%2815%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%20%2B%20%280.85%5C%2Ckg%29%5Ccdot%20%280%5Cfrac%7Bm%7D%7Bs%7D%20%29%20%3D%20%289%5C%2Ckg%29%5Ccdot%20v%20%2B%20%280.85%5C%2Ckg%29%5Ccdot%20%2845%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29)
The velocity of the bowling ball after the collision is:
![v = 10.75\,\frac{m}{s}](https://tex.z-dn.net/?f=v%20%3D%2010.75%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)