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3 years ago

12

Is 0.7÷10 equal to 0.07

1 answer:

Vlada [557]3 years ago

6 0

Yes, it is 0.7/10=0.07

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(Kinda need help ASAP)

denis23 [38]

Answer:

Plzzzz answer fast......

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3 years ago

Tina Zappa purchased a three-pack of facial tissues for $2.98. What is the unit price per pack rounded to the nearest tenth of a

alexandr1967 [171]

2.98/3=.993 repeating
=$99.3 cents per

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3 years ago

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Help!! 5.1 q2 Algebra

ICE Princess25 [194]

Answer:

4y^2-y+21

Step-by-step explanation:

(4y-5y)+(5y^2-y^2)+(-6+27)

-y+4y^2+21

put it in standard form

4y^2-y+21

6 0

3 years ago

The greatest common factor (GCF) of x^3, x^7, x^9 is ?<br> Please help

solong [7]

Answer:

$x^3$

Step-by-step explanation:

Let the greatest common factor of $a,b,c$ such that $a,b,c \in\mathbb{Z}$ and they are not all equal to zero, $d$ is the common divisor of $a$ and $b$ . Therefore, $d \mid a$ and $d \mid b$

You can write

$D(a) = \{d \in\mathbb{Z} : d \mid a\}$

$D(b) = \{d \in\mathbb{Z} : d \mid b\}$

The greatest common factor of $a,b$ is given as

$D(a,b) = \{d \in\mathbb{Z} : d \mid a \text{ and } d \mid b\}$

and

$D(a, b) = D(a) \cap D(b)$

This happens because $D(a,b)$ is upper bounded because if $a\neq 0$ then $d \leq |a|$

for all $d\in D(a, b)$ . Therefore, the set $D(a, b)$ has the greatest elements.

Taking $x^3, x^7, x^9$ such that $x>0$

You can note that $x^7 = x^3 \cdot x^4$ and $x^9 = x^3 \cdot x^6 = x^3 \cdot x^3 \cdot x^3$

Therefore, the greatest common factor is $x^3$

Note: $x^3 \cap x^7 \cap x^9 = x^3$

6 0

3 years ago

Which one is your favorite

nataly862011 [7]

I like the first one and tje third one

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3 years ago

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