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alexira [117]
3 years ago
9

Please help me with this: Create 20 bullet points specifically about energy exchanges in Earth's systems. Also, it doesn't have

to be in 20 bullet points as long as it is about energy exchanges in Earth's systems in full paragraph that is fine too.
Chemistry
2 answers:
raketka [301]3 years ago
7 0

The below is about the energy exchanges in earth systems.                                                                                                          

<u>Explanation</u>:

  • Energy exchanges in earth systems are of many types.  The earth systems are atmosphere, geosphere, stratosphere, hydrosphere, and biosphere. All these earth systems exchange energy with each other.
  • The earth gains energy reflected from the sky. It converts that energy back to space. That energy is equally given to all the planets in the sky.
  • Each planet will absorb that energy and radiate heat. This heat is absorbed by all the places on the earth. So this is the energy exchange in the earth systems.                                                                                
maxonik [38]3 years ago
4 0

Energy exchanges in Earth's system revolves around Earth's main energy outputs which are visible and infrared radiation, reflected light and thermal infrared radiation. ultraviolet radiation and visible radiation,  gamma rays, X-rays and ultraviolet radiation.

Explanation:

  • Energy exchanges in Earth's system revolves around Earth's main energy outputs which are
  • visible and infrared radiation,
  • reflected light and thermal infrared radiation.
  • ultraviolet radiation and visible radiation,  
  • gamma rays,
  • X-rays and ultraviolet radiation.
  • The Sun, which makes the external processes that occur in the atmosphere, hydrosphere, and at Earth's surface,
  • The heat flowing from Earth's interior give power to the internal processes that produce volcanoes, earthquakes, and mountains.
  • The Sun also radiates huge amounts of energy.
  • Only a small portion of that energy hits the Earth, but it is enough to light our days, heat our air and land and it creates weather systems over the oceans and seas.
  • When the Sun's energy moves around the space, it reaches Earth's atmosphere and finally to the surface.
  • This heat energy is transferred throughout the planet's systems in three ways which are
  • by radiation,
  • by conduction, and
  • by convection.

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Equal numbers of moles of He(g), Ar(g), and Ne(g) are placed in a glass vessel at room temperature. If the vessel has a pinhole-
mrs_skeptik [129]

Answer:

VP as function of time => VP(Ar) > VP(Ne) > VP(He).

Explanation:

Effusion rate of the lighter particles will be higher than the heavier particles. That is, the lighter particles will leave the container faster than the heavier particles. Over time, the vapor pressure of the greater number of heavier particles will be higher than the vapor pressure of the lighter particles.

=> VP as function of time => VP(Ar) > VP(Ne) > VP(He).

Review Graham's Law => Effusion Rate ∝ 1/√formula mass.

4 0
3 years ago
1. Determine the final volume of a 1.5 M HCl solution prepared from 20.0 mL
nadezda [96]

Explanation:

Because molarity is classified as moles of solute per liter of water, dilution of the water may result in a reduction of its concentration.

Therefore, because the amount of moles of solute has to be constant for dilution, you will use the molarity and volume of that same target solution to calculate how many moles of solute will be present in the sample of the stock solution that you dilute.

c  =   \frac{n}{v}

⇒  n = c ⋅  V

n_{HCL} =  0.250 M  ⋅  6.00 L  = 1.5 moles HCl

Now all you have to do is figure out what volume of   6.0 M  stock solution will contain  1.5  moles of hydrochloric acid

c = \frac{n}{v}

V = \frac{n}{c}

V_{Stock} = \frac{1.5 moles}{6.0 \frac{moles}{L} }   = 0.25 L

Expressed in milliliters, the answer will be

V_{Stock} = 250ML →  rounded to two sig figs

7 0
3 years ago
Given that the ksp of aipo4 is 9.84 x 10-21 at 25°c, calculate the molar solubility of aiop4
svp [43]
AlPO4----> Al+3 + PO4-3

Ksp= [Al+3] x [PO4-3]= 9.84 x 10^-21

Ksp= (x) (x)= x^2
 
X^2= 9.84x10-21
 
x= 9.92 x 10^-11

The molar solubility is 9.92 x 10^-11
8 0
3 years ago
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Answer:

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4 0
4 years ago
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How many moles would be in 85.OmL of 0.750M KOH?
Harlamova29_29 [7]

Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

Explanation:

Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity = 0.750 M

It is known that molarity is the number of moles of solute present in liter of a solution.

Therefore, moles present in given solution are calculated as follows.

Molarity = \frac{moles}{Volume (in L)}\\0.750 M = \frac{moles}{0.085 L}\\moles = 0.0637 mol

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

7 0
3 years ago
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