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Anna007 [38]
3 years ago
9

Calculate the man’s height . (Use PE = m × g × h, where g = 9.8 N/kg.)

Chemistry
1 answer:
monitta3 years ago
3 0
From the formula PE = mgh, find h.

Divide both sides for mg (because we have them) so we have PE/mg = mgh/mg

h = PE/mg

h = 4620 J/ (56 kg * 9,8 N/kg)

h = 4620 J / 548.8 N = 8.4 m (circa)
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3 years ago
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How many milliliters of sterile water for injection should be added to a vial containing 5 mg/mL of a drug to prepare a solution
jonny [76]

Answer:

7mL of sterile water is the initial amount of the concentrated solution is 3mL

Explanation:

In this problem, the vial must be <em>diluted </em>from 5mg/mL to 1.5mg/mL, that means the solution must be diluted:

5mg/mL / 1.5mg/mL = 3.33 times

If the initial amount of the drug in the vial is 3mL, the final volume must be:

10mL

That means the volume of water that should be added is:

10mL - 3mL:

<h3>7mL of sterile water is the initial amount of the concentrated solution is 3mL</h3>
4 0
3 years ago
How many milliliters of a 0.40%(w/v) solution of nalorphine must be injected to obtain a dose of 1.5 mg?
ozzi
The number  of Ml  of  a  0.40 %w/v solution  of   ,nalorphine  that must  be injected  to  obtain  a  dose  of 1.5 mg is  calculated as  below


since M/v%   is  mass  of solute  in  grams per 100  ml

convert Mg to  g
1 g = 1000 mg  what  about  1.5 mg =?  grams
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6 0
3 years ago
a compound is 21.20% nitrogen,6.06% hydrogen, 24,30% sulfur, and 48.45% oxygen. write the empirical formula and name the compoun
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The numbers may be off by a few, if you worked it out, since my periodic table is for AP chemistry. Hope this helps!!!

4 0
3 years ago
What is the molarity of a solution containing 55.8 g of mgcl2 dissolved in 1.00 l of solution?
MakcuM [25]
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So, 1 mol has 95.2 g/l.

Our solution contains 55.8g in 1 l  of solution, which is 55.8 g/l

Now, we need to make a proportion:
1 mole has 95.2 g/l, how much moles will have 55.8 g/l:
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x = 1 M · 55.8 g/l ÷ 95.2 g/l ≈ 0.59 M
7 0
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