Explanation:
Defining law of definite proportions, it states that when two elements form more than one compound, the ratios of the masses of the second element which combine with a fixed mass of the first element will always be ratios of small whole numbers.
A. One of the oxides (Oxide 1) contains 63.2% of Mn.
Mass of the oxide = 100g
Mass of Mn = 63.2 g
Mass of O = 100 - 63.2
= 36.8 g
Ratio of Mn to O = 63.2/36.8
= 1.72
Another oxide (Oxide 2) contains 77.5% Mn.
Mass of oxide = 100 g
Mass of Mn = 77.5 g
Mass of O = 100 - 77.5
= 22.5 g
Ratio of Mn to O = 77.5/22.5
= 3.44
Therefore, the ratio of the masses of Mn and O in Oxide 1 and Oxide 2 is in the ratio 1.72 : 3.44, which is also 1 : 2. So the law of multiple proportions is obeyed.
B.
Oxide 1
Mass of Mn per 1 g of O = mass of Mn/mass of O
= 77.5/22.5
= 3.44 g/g of Oxygen.
Oxide 2
Mass of Mn per 1 g of O = mass of Mn/mass of O
= 77.5/22.5
= 3.44 g/g of Oxygen.
Answer:
Clavulanic acid has two (2) chiral centers.
Explanation:
A chiral center is a center (usually carbon) with four different substituents.
The structure of clavulanic acid is shown in the attachment below.
Consider the labeled diagram in the attachment,
Carbon A is not a chiral carbon because it has two hydrogen atoms attached to it
Carbon B is not a chiral carbon because it has only three substituents
Carbon C is a chiral carbon because it has four different substituents
Carbon D is a chiral carbon because it has four different substituents
Carbon E is not a chiral carbon because it has only three atoms directly attached to it
Carbon F is not a chiral carbon because it has only three atoms directly attached to it
Carbon G is not a chiral carbon because it has two hydrogen atoms attached to it
Carbon H is not a chiral carbon because it has only three substituents
Then, only carbons C and D are chiral carbons.
Hence, clavulanic acid have two (2) chiral centers.
Answer:
1s2 2s2 2p6 3s2 3p6 3d6 4s2
Explanation:
The water cycle is one interaction between the geosphere and the cryosphere.
Explanation:
Start with a balanced equation.
2H2 + O2 → 2H2O
Assuming that H2 is in excess, multiply the given moles H2O by the mole ratio between O2 and H2O in the balanced equation so that moles H2O cancel.
5 mol H2O × (1 mol O2/2 mol H2O) = 2.5 mol O2
Answer: 2.5 mol O2 are needed to make 5 mol H2O, assuming H2 is in excess.
