The domain is a discrete set. So we will have a discrete range.
The range is a set containing:
f(-2)=-11
f(-1)=-9
f(0) = -7
f(1) = -5
f(2) = -3
Range = {-11,-9,-7,-5,-3}
Answer: She would need 206 paper cups.
Step-by-step explanation: First of all, Monica has a 10-gallon container full of lemonade and this translates into 37850 cubic centimetres volume of lemonade. The conversion rate has been provided as one gallon equals 3785 cubic centimetres, therefore ten gallons would be 3785 times ten which gives you 37,850 cubic centimetres of lemonade.
Each cone shaped paper cup has a diameter measuring 8 centimetres and 11 centimetres in height. The radius of the cone shaped cup therefore is 4 centimetres (radius equals diameter divided by two). The volume of each cup therefore is given as;
Volume of a cone = (πr²h)/3
Volume of a cone = (3.14 * 4² * 11)/3
Volume of a cone = 552.64/3
Volume of a cone = 184.2
If each cone could hold 184 cubic centimetres of lemonade, then the entire ten gallons would require the following number of cone shaped cups;
Number of cups = Total volume/Volume of a cup
Number of cups = 37850/184.2
Number of cups = 205.48
Rounded to the nearest whole number, this becomes
Number of cups ≈ 206
Therefore Monica would need 206 cone shaped paper cups to empty the entire 10 gallons of lemonade.
Answer: The correct answer is option C: Both events are equally likely to occur
Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;
P(>3) = Number of required outcomes/Number of possible outcomes
P(>3) = 3/6
P(>3) = 1/2 or 0.5
Therefore the probability of rolling a number greater than three is 0.5 or 50%.
For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;
P(Head) = Number of required outcomes/Number of all possible outcomes
P(Head) = 1/2
P(Head) = 0.5
Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on a tail is equally 0.5 or 50%)
From these results we can conclude that in both experiments , both events are equally likely to occur.
Answer:
Where is the shape?
Step-by-step explanation:
