All categories

2 years ago

Find the value of x in the triangle

Mathematics

2 answers:

Ludmilka [50]2 years ago

8 0

Answer:

2√13

Step-by-step explanation:

By pythagoras theorem:

x² = 6² + 4²

x² = 36 + 16

x² = 52

x = 2√13

miss Akunina [59]2 years ago

5 0

Answer: $\sqrt{52}$

Step-by-step explanation:

a^2 +b^2 = c^2

4^2 = 16

6^2 = 36

16+36=52

c^2=52

c= $\sqrt{52}$

You might be interested in

HELPPPPP ASAP!!!! I’m on a limit

nadezda [96]

Answer:

<h2>look at the photo.........</h2>

3 0

1 year ago

Read 2 more answers

EASY- Han has to build the figure below, which will serve as a counterweight, for his robotics project. Find the VOLUME of the f

Ymorist [56]

Given:

A combined figure of a triangular prism and a cuboid.

To find:

The volume of the finished object assuming it is empty inside.

Solution:

From the given figure it is clear that the dimensions of the cuboid are 6 cm, 8 cm and 5 cm.

So, the volume of the cuboid is:

$V_1=length\times width\times height$

$V_1=6\times 8\times 5$

$V_1=240$

The volume of the cuboid is 240 cubic cm.

The area of a triangle is:

$Area=\dfrac{1}{2}\times base\times height$

Thus, the base area of the triangular prism whose base is 8 cm and height 4 cm, is:

$B=\dfrac{1}{2}\times 8\times 4$

$B=16$

The volume of a triangular prism is:

$V_2=Bh$

Where, B is the base area and h is the height of the prism.

The base area of the triangular prism is 16 square cm and the height is 5 cm. So, the volume of a triangular prism is:

$V_2=16(5)$

$V_2=80$

Now, the volume of the given figure is:

$V=V_1+V_2$

$V=240+80$

$V=320$

Hence, the volume of the finished object is 320 cubic cm.

7 0

1 year ago

Nando has 2 goldfish. Jill has 5 goldfish Cooper has 2 times as many goldfish as Nando and Jill combined

kolezko [41]

Answer:

cooper has 14 goldfish

Step-by-step explanation:

because cooper has 2 times as many as Nando (2) and Jill (5) combined so 7 ( 5+2) times 2 is 14. 14 goldfish

3 0

2 years ago

Read 2 more answers

what is the common ratio of the geometric sequence below? –96, 48, –24, 12, –6, ... a, -2 b,-1/2 c, 2 d, 1/2

marysya [2.9K]

Answer:

Option b is correct.

The common ratio for the given geometric sequence is; $\frac{-1}{2}$

Step-by-step explanation:

The given sequence is; -96, 48 , -24, 12 , -6, .....

Since, given sequence is Geometric

Geometric Sequence in which each term is found by multiplying the previous term by a constant(i.e common ratio)

In general we write geometric sequence as;

$a , ar, ar^2, ar^3 , .....$

where a be the first term and r is the common ratio.

On comparing the given sequence with general geometric sequence;

we get

a = -96 ......[1]

ar = 48 ......[2]

ar^2 = -24 .....[3]

and so on....

To find the common ratio i.e, r;

Divide equation [2] by [1];

$\frac{ar}{a} =\frac{48}{-96}$

Simplify:

$r = \frac{-1}{2}$

Similarly,

by dividing the equation [3] by [2] we get;

$\frac{ar^2}{ar} = \frac{-24}{48}$

Simplify:

$r = \frac{-1}{2}$

As, you can see that the value of r is constant i.e, $r= \frac{-1}{2}$ in the given sequence.

Therefore, the common ratio for the given geometric sequence is; $r= \frac{-1}{2}$

8 0

2 years ago

Read 2 more answers

The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in

Anon25 [30]

We have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is $[2,\infty)$ .

If we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

Let us know find its inverse.

$y=(x-5)^{2}+2$

Upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

Let us now solve this function for y.

$(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\$

Hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

8 0

2 years ago