1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer:
function g is positive over (-∞, ∞)
function g has a y-intercept of (0,4)
function g decreasing over the interval (-∞, 0)
Step-by-step explanation:
19 minutes ..
Divides 45.85 by 15 you will get 3 same for the other cost- the divide 3 by 55.81 and you get 19
Answer:
1. f - 2g
2. im sorry i cant figure it out
Step-by-step explanation:
Answer:
I only know one way and its x = 7
Step-by-step explanation:
20 = 5( x -3 )
20/5 = x- 3
4 = x - 3
4 + 3 = x
7 = x
