2y - x = 5
x^2 + y^2 - 25 = 0
x = 2y - 5
(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4
x = 2y - 5 , when y = 0
x = - 5
x = 2y - 5 , when y = 4
x = 8 - 5
x = 3
Answer:
17
Step-by-step explanation:
Look at any 2 adjacent numbers and find the difference between them.
Starting with numbers 1 and 2, subtract the first from the second:

That's a difference of 8, meaning the second number increased by 8.
Check the next numbers, 2 and 3:

It increased by 8 again. Now that we know for sure that each term in the sequence increases by 8 over the previous one, we can find the number in the green box. Just add 8 to the number before it:
