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ollegr [7]
2 years ago
8

Please solve the whole page please please

Mathematics
1 answer:
Leya [2.2K]2 years ago
4 0

1d) ↑ (Do the same but turned if that's easier)

1a) 199

1b) 193

1c) 217

1e) Based on the box plot, we can for example, find the lowest and greatest values, the range (largest - smallest), the mean (all values / # values), and the median middle value or q2 given by the second line in the box.

2b) 7

2c) 9.5

2d) ↑

2e) because the data is not ordered, it is difficult to determine the quartile data. Once it is ordered like 6, 7, 7, 7, 8, 8, 9, 10, 10. The data can be visualized alot easier. With the box plot we can determine q3 of the data by looking at the 3rd line, using the whiskers of the box to find the minimum and maximum values.

3)

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be: 4,6,8,8,9,11,12,14,14,16.

[4, 6, 8, 8, 9] [] [11, 12, 14, 14, 16]

4 is the minimum, 16 is the maximum, q1 is 8, q3 is 14, and median is 10.

4) ↑

5)

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be:

45, 45, 50, 55, 60, 70, 70, 75, 80, 85

[45, 45, 50, 55, 60] [] [70, 70, 75, 80, 85]

45 is the minimum, 85 is the maximum, q1 is 50, q3 is 75, and median is 65.

6) ↑

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In a random sample of n1 = 162 males, there are x1 = 63 people that have blue eyes. In a random sample of n2 = 333 females, ther
sesenic [268]

Answer:

z = 2.1784 > 1.96,

Reject the null hypothesis

Step-by-step explanation:

For the males:

n1  = 162, x1 = 63

P1 = x 1/ n1 = 0.3889

For the Females:

n2 = 333,

x2 = 97

P 2 = x2/n2

= 0.2913

P 1= P2 Null hypothesis

P 1 is not equal to P 2 alternative hypothesis

Pooled proportion:

P= (x1 + x2) /( n1+ n2)

= (63 + 97) / (162 + 333)= 0.3232

Test statistics :

Z= (p1 - p2) /√p(1-p)× (1/n1 + 1/n2)

0.3889- 0.2913 / √0.3232 × 0.6768 × (1/162 +1/333)

=2.1784

c) Critical value :

Two tailed critical value, z critical = Norm.S .INV (0.05/2) = 1.960

Reject H o if z < -1.96 or if z > 1.96

d) Decision:

z = 2.1784 > 1.96,

Reject the null hypothesis

7 0
3 years ago
What 1,045 to the nearest thousands
faltersainse [42]

1,045 to the nearest thousands would be <u>1,000</u> because you must round down since there are no numbers close enough to round up.

8 0
4 years ago
Read 2 more answers
For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec
telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

4sin(x^2) = 0

sin(x^2) = 0

x^2 = n\pi where n = 0, 1, 2,3, 4, 5,...

x = \sqrt(n\pi)

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0

xcos(x^2) = 0

x = 0 or

cos(x^2) = 0

x^2 = \frac{\pi}{2} + n\pi where n = 0, 1, 2, 3

x = \sqrt{\pi(n+1/2)}

Since we are restricting x between 0 and 3 we can stop at n =  2

So our critical points are at

x = 1.25, y = f(1.25) = 4sin(1.25^2) = 4

x = 2.17 , y = f(2.17) = 4sin(2.17^2) = -4

x = 2.8, y = f(2.8) = 4sin(2.8^2) = 4

For the inflection point, we can take the 2nd derivative and set it to 0

f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0

cos(x^2) = 2x^2sin(x^2)

tan(x^2) = \frac{1}{2x^2}

We can solve this numerically to get the inflection points are at

x = 0.81, y = f(0.81) = 4sin(0.81^2) = 2.44

x = 1.81, y = f(1.81) = 4sin(1.81^2) = -0.54

x = 2.52, y = f(2.52) = 4sin(2.52^2) = 0.27

3 0
3 years ago
How do you find sin 30 of a unit circle?
Gwar [14]
Go to where 30 degrees is on the unit circle and find the y-coordinate. That is sin30.
5 0
3 years ago
There are 25 trees on the Jackson’s property. Twenty percent of the trees are oak trees. Which equation can be used to find the
ahrayia [7]

Answer:

StartFraction 25 divided by 1 Over 20 divided by 1 EndFraction = StartFraction 25 Over 20 EndFraction

Step-by-step explanation:

Number of trees = 25

Percentage of aok trees = 20%

To obtain the Number of oak trees :

(Number of trees ÷ 1) ÷ (percentage ÷1)

(25 / 1) ÷ (20 / 1) = (25 /1) * (20 / 1) = 25 / 20

StartFraction 25 divided by 1 Over 20 divided by 1 EndFraction = StartFraction 25 Over 20 EndFraction

8 0
3 years ago
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