Bot 2 will click more times in 10 seconds, because when you divide 16 by 2 to get its unit rate it is 8 clicks per second. Times that by 10 and you only get 80, whereas if you divide 30 by 3 the unit rate is 10. At this rate, by 10 seconds it will have clicked 100 times. Bot 2 clicks 20 more times than Bot 1 in 10 seconds.
Step-by-step explanation:
if x-4 is a factor of 2x^3 + x^2- 26x - 40
then f(4) = 0
f(x) = 2x^3 + x^2- 26x - 40
f(4) = 2(4)^3 + (4)^2 - 26(4) - 40
f(4)= 2(64) + 16 - 104 - 40
f(4) = 128 + 16 - 104 - 40
f(4) = 0
hence factorize completely is the photo
3 carries of 8 yds.....3 * 8 = 24 yds
5 carries of 6 yds.....5 * 6 = 30 yds
so we have a total of 8 carries for 54 yds..
54/8 = 6.75 <== average yds per carry
Answer:
<u><em>y=7 </em></u><u>number of hours at grocery store</u>
<u><em>x=18 </em></u><u>number of hours at baby- sitting</u>
Step-by-step explanation:
According to the information provided.
x is number of hours at baby- sitting
y is number of hours at grocery store
total number of hours worked
<em>1) </em><em>x+y =25</em>
total earn in a week
<em>2) </em><em>x*$6 + y* $9 = $171</em>
<em />
<em>from equation 1</em>
x+y=25
x= 25-y
<em>we place the above derived equation in equation 2 </em>
x*$6 + y* $9 = $171
(25-y)*$6 + y* $9 = $171
(25*6) -6y +9y =171
150+3y=171
3y=171-150
3y=21
<u><em>y=7 </em></u><u>number of hours at grocery store</u>
x= 25-y
x= 25-7
<u><em>x=18 </em></u><u>number of hours at baby- sitting</u>
Let
x-------> the amount of 
solution
y--------> the amount of 
solution
we know that
so
-------> equation A
-------> equation B
substitute equation A in equation B
find the value of y
therefore
The student need 
of solution and 
of solution
<u>the answer is</u>
A) The percent values were written incorrectly in the equation
B) The amount of 7% solution should be written as 1 – x, not x – 1.
