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user100 [1]
3 years ago
15

Please help with this problem:

Mathematics
1 answer:
Olegator [25]3 years ago
6 0
He added 8 to both sides. He did the write thing.
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Solve 9x−y=45 for y.
Taya2010 [7]

So to solve for y, we need to get y alone on one side of the equation. So we are going to subtract 9x from both sides of the equation to get:

-y=-9x+45

And since y is negative, we are going to divide both sides by -1 in order to make the y positive:

y=9x-45

4 0
3 years ago
Pls help I literally am crying I don’t understand ):
damaskus [11]

Answer: Passes out in slow

Step-by-step explanation:

Step 1 be Einstein

6 0
2 years ago
PLZ HELP ASAP CONGRUENCE GEOMETRY
RoseWind [281]
The answer is 80 degrees. As you can see, the triangle is an isosceles triangle and both sides of the triangle equal 14. If both of the sides are congruent then the opposite angles are also congruent as well. Which means the 50 degrees in the left angle is congruent to the right angle, 50. Since triangles add up to 180 degrees, the answer for x would be 80. 

Hope this helped :)
4 0
3 years ago
what is the volume of is a rectangular prism that is 14 inches long, 7 inches wide, and 10 inches high?
igomit [66]

Answer:

Step-by-step explanation:

980

7 0
2 years ago
You are planning a survey of starting salaries for recent computer science majors. In a recent survey by the National Associatio
nydimaria [60]

Answer:

A sample size of 554 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Standard deviation is known to be $12,000

This means that \sigma = 12000

What sample size do you need to have a margin of error equal to $1000, with 95% confidence?

This is n for which M = 1000. So

M = z\frac{\sigma}{\sqrt{n}}

1000 = 1.96\frac{12000}{\sqrt{n}}

1000\sqrt{n} = 1.96*12

Dividing both sides by 1000:

\sqrt{n} = 1.96*12

(\sqrt{n})^2 = (1.96*12)^2

n = 553.2

Rounding up:

A sample size of 554 is needed.

5 0
2 years ago
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