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olchik [2.2K]
3 years ago
7

Explain the law of conservation of energy in your own words .

Physics
1 answer:
melamori03 [73]3 years ago
4 0
The law of conservation of energy states that in any reaction, energy cannot be created or destroyed.

In other words, energy has to be conserved in every reaction.
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An object starts from rest and accelerates to a velocity of 10 m/s, east in 5 seconds. What is the acceleration of the object?
Shalnov [3]

Answer:

2m/s²

Explanation:

acceleration is the rate of change of velocity

for velocity to reach 10m/s in 5s,

acceleration= 10/5

=2

3 0
4 years ago
How does the shape of an plane wing help it to lift off the ground and fly
Licemer1 [7]
<span>a planes engines are designed to move it forward at high speed. That makes air flow rapidly over the </span>wings<span>, which throw the air down toward the </span>ground<span>, generating an upward force called </span>lift<span> that overcomes the </span>plane's<span> weight and holds it in the sky. ... The </span>wings<span> force the air downward and that pushes the </span>plane<span> upward</span>
8 0
3 years ago
What is the equation for an inelastic collision
abruzzese [7]
M1 v1 = (m1 + m2)v2.

All of the exponents should be lowered to the bottom right of the letters.
7 0
3 years ago
A neutron consists of one "up" quark of charge +2e/3 and two "down" quarks each having charge -e/3. If we assume that the down q
Anon25 [30]

Answer:

The magnitude of the electrostatic force is 120.85 N

Explanation:

We can use Coulomb's law to find the electrostatic force between the down quarks.

In scalar form, Coulomb's law states that for charges q_1 and q_2 separated by a distance d, the magnitude of the electrostatic force F between them is:

F = k \frac{|q_1q_2|}{d^2}

where k is Coulomb's constant.

Taking the values:

d = 4.6 \ 10^{-15} m

q_1 = q_2 = - \frac{e}{3} = - \frac{1.6 \ 10^{-19} \ C}{3}

and knowing the value of the Coulomb's constant:

k = 8.99 \ 10 ^{9} \frac{N m^2}{C^2}

Taking all this in consideration:

F = 8.99 \ 10 ^{9} \frac{N m^2}{C^2} \frac{ (- \frac{1.6 \ 10^{-19} \ C}{3} ) ^2}{(4.6 \ 10^{-15} m)^2}

F = 120.85  \ N

8 0
3 years ago
50 POINTS! Chipping from the rough, a golfer sends the ball at an angle of 54° with an initial velocity of 13m/s, how far down t
docker41 [41]

Range equation:

x=\dfrac{{v_i}^2\sin2\theta}g

This ball travels a distance of

x=\dfrac{\left(13\frac{\rm m}{\rm s}\right)^2\sin108^\circ}{9.8\frac{\rm m}{\mathrm s^2}}=16\,\mathrm m

5 0
3 years ago
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