When is thermal equilibrium achieved between two identical objects?

Do electromagnetic waves travel through a medium

vladimir1956 [14]

No, they actually travel through the vacuum of outer space, but it also requires the absence of a material sedium.

3 0

4 years ago

1 pts

Nuetrik [128]

Answer:

The leaf cells would be unable to convert the sun's energy to make food.

Explanation:

The chloroplast in the leaf are used to make food for the plant. If the leaf loses its chloroplast, the leaf with not be able to use solar energy to manufacture their food.

During photosynthesis, green plants manufacture their food.
They use sunlight to cause a reaction between carbon dioxide and water.
The sunlight is trapped using chlorophyll present in the leaf.
In the absence of the chlorophyll contained in the chloroplast, no solar energy would be generated to cause the reaction to take place.

4 0

3 years ago

Two point charges, q1 = 2.0 × 10−7 C and q2 = −6.0 × 10−8 C, are held 25.0 cm apart. (a) What is the electric field at a point 5

AlladinOne [14]

Answer:

a) $432000\frac{N}{C}\hat{i}$

b) $-6.92\times10^{-14}N\hat{i}$

Explanation:

a)

The magnitude of the electric field generated by a charged particle at a distance r is:

$E= k\frac{|Q|}{r^{2}}$

With Q the charge of the particle and k the constant ()

So, the electric field generated by q1 knowing that the point 5.0 cm apart the negative charge is $25.0cm-5.0cm=20.0 cm=0.2m$ apart the positive charge is:

$E_1= k\frac{|q1|}{r_1^{2}} =(9.0\times10^{9}\,\frac{Nm^{2}}{C^{2}})\frac{|2.0\times10^{-7}|}{(0.2)^{2}}$

$E_1= 45000\frac{N}{C}$

and the electric field generated by q2:

$E_2= k\frac{|q2|}{r_2^{2}} =(9.0\times10^{9}\,\frac{Nm^{2}}{C^{2}})\frac{|-6.0\times10^{-8}|}{(0.05)^{2}}$

$E_2=216000\frac{N}{C}$

Those are the magnitudes of the electric field, but electric field is a vector quantity, so the direction is important. Electric field generated by negative particles points towards the charge and electric field generated by positive particles points away the particle. So, if we define positive direction towards negative particle (x-axis):

$\overrightarrow{E_2}=+216000\frac{N}{C}\hat{i}$

$\overrightarrow{E_1}= +45000\frac{N}{C}\hat{i}$

Vector quantities satisfy superposition principle, this is $\overrightarrow{E}=\overrightarrow{E_1}+\overrightarrow{E_2}$ , with E the total electric field.

$\overrightarrow{E}=(216000+45000)\hat{i}=432000\frac{N}{C}\hat{i}$

b) The force is:

$\overrightarrow{F}=e*\overrightarrow{E}$ ,

with q the charge of an electron

$\overrightarrow{F}=(-1.61\times10^{-19})*(432000)\hat{i}=-6.92\times10^{-14}N\hat{i}$

8 0

3 years ago

Minnie sota hits the end of a bar 1. 2 m long with a hammer. Sketch the standing wave on the bar for the following situations. T

ella [17]

(a) The wavelength of the wave for the fundamental mode is 2.4 m.

(b) The fundamental frequency of the wave is 2,708.33 Hz.

<h3>Wavelength of the wave for fundamental mode</h3>

The wavelength of the wave for the fundamental mode is calculated as follows;

Node to Node, N → N = λ/2

L = λ/2

λ = 2L

λ = 2 x 1.2

λ = 2.4 m

<h3>Fundamental frequency of the wave</h3>

The fundamental frequency of the wave is calculated as follows;

f = v/λ

f₀ = v/2L

f₀ = (6500)/(2 x 1.2)

f₀ = 2,708.33 Hz

The diagram of the wave for the fundamental mode is in the image uploaded.

Learn more about wavelength here: brainly.com/question/10728818

5 0

2 years ago

An astronaut in an inertial reference frame measures a time interval Δt between her heartbeats. What will observers in all other

Reika [66]

Answer:

It will be more than deta t

Explanation:

Because

deta t' = န deta t

But န= 1/√ (1 - v²/c²

So the observers in all the initial frames will be more than deta t

3 0

4 years ago