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julia-pushkina [17]
3 years ago
9

How many grams in 10 ounces

Chemistry
2 answers:
Kamila [148]3 years ago
8 0

Answer:

283.495g

Explanation:

Goshia [24]3 years ago
3 0

Answer:283.50

Explanation:

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Two trials are run, using excess water. In the first trial, 7.8 g of Na2O2(s) (molar mass 78 g/mol) is mixed with 3.2 g of S(s).
Tema [17]

Answer:

The answer is "Option C".

Explanation:

Given equation:

2Na_20_2 (s)+S(s)+2H_2O \longrightarrow  4NaOH(aq)+SO_2(aq)

\to \Delta H^{\circ}_{rxn} (298\ K) = -610 \frac{kJ}{mol}

\to Na_2O_2  \ Mass = 7.8 \ g\\\\ \to  Na_2O_2 \ Molar \ mass = 78 \frac{g}{mol}

Na_2O_2 Has been the reactant which is limited since the two experiments are equal toNa_2O_2 for relationship between stress amounts.

Na_2O_2, n =\frac{Mass of Na_2O_2}{Molar mass of Na_2 O_2}=\frac{7.8 \ g}{78 \frac{g}{mol}} =0.1 \ mol \\\\q=\Delta H^{\circ}_{rxn} \times n = \frac{ -610 \ kJ}{ 2 \ mol \ Na_2 O_2} \times 0.1 \ mol  \ Na_2O_2= 30.5 \ KJ\\\\

Limiting reactant =Na_2O_2

q=30.5 \ kJ \approx 30 \ kJ

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3 years ago
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What is the ratio strength of 100 ml containing a 1:50 povidone iodine solution diluted to 1000 ml? (answer must be numeric; no
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We are given that:

100 mL total solution with 1:50 povidone iodine solution

 

This means that there is 1 mL of povidone iodine solution per 50 mL of total solution. Since we are given a total of 100 mL solution, therefore we have an initial amount of:

pure povidone iodine solution = 2 mL

 

This amount of pure povidone iodine solution is added or diluted (most perhaps with water) to make a total of 1000 mL total solution, therefore the new ratio is:

2:1000 povidone iodine solution

By dividing both sides by 2, this simplifies to

1:500 povidone iodine solution

 

Answer:

1:500

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