Answer:
50.5 g/dL
Explanation:
From the question given above, the following data were obtained:
Mass of Al₂(SO₄)₃ = 101 g
Volume (V) = 200 mL
Concentration of solution (g/dL) =?
Next, we shall convert 200 mL to decilitre (dL).
This is illustrated below:
1 mL = 0.01 dL
Therefore,
200 mL = 200 mL / 1 mL × 0.01 dL
200 mL = 2 dL
Therefore, 200 mL is equivalent to 2 dL.
Finally, we shall determine the concentration of the solution in g/dL as follow:
Mass of Al₂(SO₄)₃ = 101 g
Volume (V) = 2 dL
Concentration of solution (g/dL) =?
Concentration of solution (g/dL) = mass /volume
Concentration of solution (g/dL) = 101/2
= 50.5 g/dL
Therefore, the concentration of the Al₂(SO₄)₃ solution is 50.5 g/dL
Parsec is a unit of distance (as stated 1 Parsec = 3.26 light years, wihch is 3.26 times the distance run by light in one year).
That distance is:
1 parsec = 3.26 mi× 186,000 mi/s × 3600 s/h × 24 h/day × 365 day/ year × 1 year = 19,122,168,960,000.mi.
So, the question of <span>how many parsecs it takes for light to reach Mars from Earth does not make sense because parsecs is not a unit of time.
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</span><span>You can calculate how many parsecs is equivalent to the distance between Mars and Earth, 60,000,000 km. For this you can first calculate the equivalence of which you do in this way:
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</span><span>60,000,000 km × 0,621 mi/km × 1 parsec / ( 19,122,168,960,000 mi) = 1.94E-6 parsecs.
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Answer:
3.24 mol/L
Explanation:
Given that:
mass of Boron triiodide = 6664 grams
molar mass of BI_3 = 391.52 g/mol
Recall that:
number of moles = mass/molar mass
∴
number of moles = 6664 g /391.52 g/mol
number of moles = 17.02 mol
Also;
Molarity = moles for solute/liter for solution
= 17.02 mol/5.25 L
= 3.24 mol/L
Answer:
A. Alpha decay followed by emission
Explanation:
The given nuclide is thorium-232
The product formed in the decay of thorium-232 is actinium -228
the difference between the atomic number is 1 (90-89)
the difference between the mass number is 1 (232-228)
A decrease in mass number by 4 and atomic number by 2 indicates an alpha decay.
now to get ^{228}_{89}Ac from ^{228}_{88}Ra, Radium undergoes beta emission to increase the atomic number by 1 and no change in the mass number.
Thus alpha decay followed by beta emission gives Ac-228
hence option A is correct
