Question

A body moves with constant acceleration. It's velocity increases from 6 m/s to 16 m/s in 2 seconds. The distance moved by the body in these 2 seconds is

Answer 1

Answer:

The distance moved by the body in these 2 seconds is 22 meters.

Explanation:

Given that,

Initial velocity of a body, u = 6 m/s

Final velocity of the body, v = 16 m/s

Time, t = 2 s

Let d is the distance moved by the body in these 2 seconds is. Using third equation of motion to find it such that,

$v^2-u^2=2ad\\\\(16)^2-(6)^2=2\times (\dfrac{16-6}{2})\times d\\\\d = 22\ m$

So, the distance moved by the body in these 2 seconds is 22 meters. Hence, this is the required solution.