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3 years ago

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What is the wavelength of an electromagnetic wave

1 answer:

VMariaS [17]3 years ago

3 0

Answer:

Explanation:

Electromagnetic waves are categorized according to their frequency f or, equivalently, according to their wavelength λ = c/f. Visible light has a wavelength range from ~400 nm to ~700 nm.

The electromagnetic spectrum (EMS) is the general name given to the known range of electromagnetic radiation. Wavelengths increase from approximately 10-18 m to 100 km, and this corresponds to frequencies decreasing from 3 × 1026 Hz to 3 ×103 Hz.

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What supports a white dwarf against the crush of gravity?

weqwewe [10]

Answer: In particular, electron degeneracy pressure is what supports white dwarfs against gravitational collapse, and the Chandrasekhar limit (the maximum mass a white dwarf can attain) arises naturally due to the physics of electron degeneracy.

Explanation:

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3 years ago

The Capacitive reactance of a 0.094uF capacitor when a frequency of 25kHz is applied is lus 68 Ohms 0.68 Ohms luf

Nana76 [90]

Answer:

Capacitive reactance of the capacitor is 68 ohms

Explanation:

It is given that,

Capacitance, $C=0.094\ \mu F=0.094\times 10^{-6}\ F$

Frequency, $f=25\ kHz=25\times 10^3\ Hz$

Capacitive reactance is given by :

$X_C=\dfrac{1}{2\pi fC}$

$X_C=\dfrac{1}{2\pi 25\times 10^3\times 0.094\times 10^{-6}}$

$X_C=67.72\ \Omega$

or

$X_C=68\ \Omega$

So, the capacitive reactance of the capacitor is 68 ohms. Hence, this is the required solution.

8 0

3 years ago

Suppose that the sun shrank in size but that its mass remained the same. What would happen to the orbit of the earth?

Minchanka [31]

Answer:

Nothing

Explanation:

The radius of the orbit of the Earth does not depend on the radius of the sun.

In fact, the gravitational attraction between the Earth and the Sun provides the centripetal force that keeps the Earth in orbit:

$G\frac{Mm}{r^2} = m\frac{v^2}{r}$

where

G is the gravitational constant

M is the mass of the sun

m is the mass of the Earth

r is the radius of the orbit of the Earth

v is the orbital speed of the earth

Re-arranging the equation for r:

$r=\frac{GM}{v^2}$

Also,

$v=\omega r$

where $\omega$ is the angular velocity of the Earth's orbit. So we can rewrite the equation as

$r=\frac{GM}{\omega^2 r^2}\\r^3 = \frac{GM}{\omega^2}$

As we see, the radius of the orbit of the Earth, r, does not depend on the mass of the Sun, so if the sun shrank in size, the orbit remains the same.

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3 years ago

During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the t

leonid [27]

The instant it was dropped, the ball had zero speed.

After falling for 1 second, its speed was 9.8 m/s straight down (gravity).

Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.

Falling for 1 second at an average speed of 4.9 m/s, is covered <em>4.9 meters</em>.

ANYTHING you drop does that, if air resistance doesn't hold it back.

7 0

3 years ago

Read 2 more answers

Which travels at a greater speed, visible or infrared light?

Ksju [112]

Infrared light because it is barely able to be seen

7 0

3 years ago