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3 years ago

9

Written Works Choose the letter of the correct answer. Write it on the space provided before the number. 1. Which of the followi

ng does not belong to Thailand musical instrument? A. Calung B. Dan Bau C. Piso D. Thon and Rammana 2.. The following are musical instrument of Laos, EXCEPT: A. Kayuthin B. Khim C. Phin D. Ranat 3.A double-headed drum which is one of the primary instruments of gamelan ensemble. A. Gedombak B. Gendang C. Kompang D. Oozi 4.What do you call the five equidistant tones in an octave? A. Irama B. Kendang C. Peloq D. Slendro 5. Which orchestra in Singapore plays ethnic music? A. Singapore court music B. Singapore religious music C. Singapore Chinese Orchestra D. Singapore Symphony Orchestra

1 answer:

Stels [109]3 years ago

8 0

Answer:

1. is A. a calung

2. is A. Kayuthin

3. is B. Gendang

4. is D Slendro

5. is D Singapore Symphony Orchestra

Explanation:

Next time space them out, have a nice day baby face :D

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a wave is represented by the equation y=0.5 sin0.6×(x-60t) where the distance x is measured in cm and time t is seconds. what is

Grace [21]

Answer:

lamda=10.5m

Explanation:

using the equation of progressive wave.

y=Asin(wt-kx)

comparing the two equations together, we have

kx=0.6x , k=0.6

k=2π/λ

0.6=2*3.142/λ

cross multiply

0.6λ=6.284

divide both sides by 0.6

λ=6.284/0.6

λ=10.47m

approximate

λ=10.5m

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3 years ago

Where does the bulk of atmosphere oxygen come from

adell [148]

The bulk of earths atmospheric oxygen comes from phytoplankton, small flower like things in the ocean.

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3 years ago

A flat loop of wire consisting of a single turn of cross-sectional area 8.20 cm2 is perpendicular to a magnetic field that incre

olga nikolaevna [1]

Answer:

The induced current is $I = 6.25*10^{-4} \ A$

Explanation:

From the question we are told that

The number of turns is $N = 1$

The cross-sectional area is $A = 8.20 cm^2 = 8.20 * 10^{-4} \ m^2$

The initial magnetic field is $B_i = 0.500 \ T$

The magnetic field at time = 1.02 s is $B_t = 2.60 \ T$

The resistance is $R = 2.70\ \Omega$

The induced emf is mathematically represented as

$\epsilon = - N * \frac{ d\phi }{dt}$

The negative sign tells us that the induced emf is moving opposite to the change in magnetic flux

Here $d\phi$ is the change in magnetic flux which is mathematically represented as

$d \phi = dB * A$

Where dB is the change in magnetic field which is mathematically represented as

$dB = B_t - B_i$

substituting values

$dB = 2.60 - 0.500$

$dB = 2.1 \ T$

Thus

$d \phi = 2.1 * 8.20 *10^{-4}$

$d \phi = 1.722*10^{-3} \ weber$

So

$|\epsilon| = 1 * \frac{ 1.722*10^{-3}}{1.02}$

$|\epsilon| = 1.69 *10^{-3} \ V$

The induced current i mathematically represented as

$I = \frac{\epsilon}{ R }$

substituting values

$I = \frac{1.69*10^{-3}}{ 2.70 }$

$I = 6.25*10^{-4} \ A$

7 0

4 years ago

An organ pipe open at both ends is 1.5 m long. A second organ pipe that is closed at one end and open at the other is 0.75 m lon

telo118 [61]

Answer:

A. 110Hz,220Hz, 330 Hz

Explanation:

for organ open at open both ends;

the length of the organ for the fundamental frequency, L = A---->N + N----->A

A---->N = λ /4 and N----->A = λ /4

L = λ /4 + λ /4 = λ /2

$L = \frac{\lambda}{2} \\\\\lambda = 2L$

λ = 2 x 1.5m = 3.0 m

Wave equation is given by;

V = Fλ

Where;

V is the speed of sound

F is the frequency of the wave

F = V/ λ

F₀ = V / 2L

Where;

F₀ is the fundamental frequency

F₀ = 330 / 2(1.5)

F₀ = 330 / 3

F₀ = 110 Hz

the length of the organ for the first overtone, L = A---->N + N----->A + A----->N + N----->A

L = 4λ /4

L = λ

λ = 1.5 m

F₁ = 330 / 1.5

F₁ = 220 Hz

Thus, F₁ = 2F₀

For open organ at one end

the length of the organ for the fundamental frequency, L = N------A

L = λ /4

λ = 4L

F₀ = V/4L

F₀ = 330 / (4 x 0.75)

F₀ = 110 Hz

the length of the organ for the first overtone, L = N-----N + N-----A

L = λ/2 + λ / 4

L = 3λ /4

F₁ = 3F₀

F₁ = 3 x 110

F₁ = 330 Hz

Thus the fundamental frequency for both organs is 110 Hz,

The first overtone for the organ open at both ends is 220 Hz

The first overtone for the organ open at one end is 330 Hz

The correct option is "A. 110Hz,220Hz, 330 Hz"

6 0

3 years ago

An object with charge -4.0μC is placed between a positively charged object to the

elena-s [515]

The net force on the -4.0μC object as a result of this net field will be -10.4 N.

<h3>What is the charge?</h3>

The matter has an electric charge when it is exposed to an electromagnetic field is known as a charge.

The electric field intensity is found as the force per unit charge.

Electric field intensity on the positive charge:

$\rm E_1 = \frac{F_1}{Q} \\\\\ \rm 1.2 N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_1 = - 4.8 \ N$

Electric field intensity on the negative charge:

$\rm E_2 = \frac{F_2}{Q} \\\\\ \rm 1.4 \ N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_2 = - 5.6 \ N$

The net charge is the algebraic sum of the two charges;

$\rm F_{net}=F_1+F_2 \\\\ F_{net}= -4.8 -5.6 \\\\ F_{net}=-10.4 \ N$

Hence, as a result of this net field, the net force on the -4.0C object will be -10.4 N.

To learn more about the charge refer to the link;

brainly.com/question/24391667

#SPJ1

4 0

2 years ago